存储过程选择json数据

Question

我一直在努力如何格式化我的存储过程以创建json字符串数据

我有这个示例查询，我需要像这样格式化json字符串

  

{＆＃34;摘要＆＃34;：＆＃34;员工更改用户名＆＃34;，＆＃34; DateModified＆＃34;：＆＃34; 2017/09/06＆＃34;，＆＃34;变化＆＃34;：[{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34 ;：＆＃34; 1＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34;：＆＃34; 10＆＃34;，＆ ＃34;新＆＃34;：＆＃34; 2＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 3＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34 ;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 4＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;，＆ ＃34;旧＆＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 5＆＃34;}]}

DECLARE @membersJSON NVARCHAR(MAX) = '[1,2,3,4,5]';
DECLARE @commiteeID INT = 10;
DECLARE @jsonData NVARCHAR(MAX);

DECLARE @jsonTable TABLE(
    Property nvarchar(max),
    old nvarchar(max),
    new nvarchar(max));

INSERT INTO @jsonTable SELECT 'test' as Property,@commiteeID AS old,m.value AS new
FROM OPENJSON(@membersJSON) as m;

SELECT * FROM @jsonTable FOR JSON PATH, ROOT ('CommitteeMembers')

目前我的输出仍然是这样的

  

{＆＃34; CommitteeMembers＆＃34;：[{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34;：＆＃34; 10＆＃34; ＆＃34;新＆＃34;：＆＃34; 1＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆＃34;：＆＃ 34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 2＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34;＆＃34;旧＆ ＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 3＆＃34;}，{＆＃34;属性＆＃34;：＆＃34;测试＆＃34; ＆＃34;旧＆＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 4＆＃34;}，{＆＃34;属性＆＃34;：＆＃ 34;测试＆＃34;＆＃34;旧＆＃34;：＆＃34; 10＆＃34;＆＃34;新＆＃34;：＆＃34; 5＆＃34;}]}

继承dbfiddle link

Answer 1

您可能需要在此处使用光标

 declare @new_Cursor as CURSOR 
 declare @Property varchar(10)   
 declare @oldValue varchar(10)   
 declare @newValue varchar(10)   
 declare @jsonResult nvarchar(max) ='{"CommitteeMembers":['
set @new_Cursor = CURSOR FOR SELECT * FROM @jsonTable FOR JSON PATH, ROOT 
('CommitteeMembers')
    OPEN @new_Cursor
    FETCH NEXT FROM @new_Cursor INTO @Property,@oldValue,@newValue
    WHILE @@FETCH_STATUS = 0
    Begin
      if(@jsonResult<>'{"CommitteeMembers":[') --To separate the objects
          begin
               set @jsonResult = @jsonResult + ','
          end 
      set @jsonResult = @jsonResult + 
'{"Property":"'+@Property+'","old":"'+@oldValue+'","new":"'+@newValue+'"}'
 FETCH NEXT FROM @new_Cursor INTO @Property,@oldValue,@newValue
    end
    CLOSE @new_Cursor
   DEALLOCATE @new_Cursor
   set @jsonResult = @jsonResult + ']}'

  select @jsonResult as Result

更新

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