Question

我有以下报告，

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这将返回所选日期范围内每个人每天的工作时间，并且工作正常：

    select E.FullName, EL.DateTimeStart, EL.DateTimeStop, E.EmployeeStatusCode, EL.ExtraMinutes,
       Sum(El.ShiftTime /60.0 + (ExtraMinutes / 60.0)) as TotalHoursWorked
FROM       dbo.Employee AS E
INNER JOIN dbo.employeelog AS EL 
ON         E.EmployeeKey = EL.EmployeeKey   
where      EL.DateTimeStart BETWEEN (@StartDate) AND (@EndDate +1)and EmployeeStatusCode = @EmployeeStatusCode
GROUP BY   FullName, EL.DateTimeStart, EL.DateTimeStop, E.EmployeeStatusCode, EL.ExtraMinutes
having     Sum(El.ShiftTime /60.0 + (ExtraMinutes / 60.0)) > 0
ORDER BY   FullName

我现在才发现问题，因为我正试图围绕结果。

我尝试使用2017-04-15 13:53:02.040 2017-04-15 14:03:41.177 C 0 0.166666 2017-04-15 14:03:41.177 2017-04-15 14:12:00.303 C 0 0.150000 2017-04-15 14:16:29.610 2017-04-15 22:22:47.953 C -30 7.600000 2017-06-08 06:30:00.000 2017-06-08 12:08:54.210 C -30 5.133333 2017-06-08 12:08:54.210 2017-06-08 12:15:53.850 C 0 0.116666 2017-06-08 12:15:53.850 2017-06-08 14:37:10.040 C 0 2.366666，但问题在于每个员工的每日时间都在四舍五入。

Round()/0.5, 0) *0.5

我们系统目前的设置方式是员工的工作时间在一周结束时2017-04-15 13:53:02.040 2017-04-15 14:03:41.177 C 0 0.000000 2017-04-15 14:03:41.177 2017-04-15 14:12:00.303 C 0 0.000000 2017-04-15 14:16:29.610 2017-04-15 22:22:47.953 C -30 7.500000 2017-06-08 06:30:00.000 2017-06-08 12:08:54.210 C -30 5.000000 2017-06-08 12:08:54.210 2017-06-08 12:15:53.850 C 0 0.000000 2017-06-08 12:15:53.850 2017-06-08 14:37:10.040 C 0 2.500000，而不是在每天结束后，所以我只需要计算总和，或者每周的总工时。抱歉，如果它令人困惑，我很困惑自己，我需要一些帮助。：P

我在ms SQL server management studio中编写我的报告，并在报告生成器中完成它们。非常感谢尼克

Answer 1

很抱歉将此评论添加到答案部分，但显然我的观点不够高，视线允许我发表评论： - ）

这是我的评论/问题，看起来您列出了每个员工和每天的时间。您是否希望添加“周累计”行？或者您是否想要计算每周的舍入金额并将其应用于每一天（这种方式听起来很复杂）？请解释一下。

Answer 2

你是否在TotalHoursWorked周围？还是我误会了？舍入到最接近的数千。

select E.FullName, EL.DateTimeStart, EL.DateTimeStop, E.EmployeeStatusCode, EL.ExtraMinutes,
       round(Sum(El.ShiftTime /60.0 + (ExtraMinutes / 60.0)),3) as TotalHoursWorked
FROM       dbo.Employee AS E
INNER JOIN dbo.employeelog AS EL 
ON         E.EmployeeKey = EL.EmployeeKey   
where      EL.DateTimeStart BETWEEN (@StartDate) AND (@EndDate +1)and EmployeeStatusCode = @EmployeeStatusCode
GROUP BY   FullName, EL.DateTimeStart, EL.DateTimeStop, E.EmployeeStatusCode, EL.ExtraMinutes
having     Sum(El.ShiftTime /60.0 + (ExtraMinutes / 60.0)) > 0
ORDER BY   FullName

需要帮助舍入结果

2 个答案: