Question

我有这个循环，每2分钟计算增加温度10度。当达到16分钟及以上时，我需要将温度固定在120度我尝试了很多解决方案，但没有一个工作？任何建议???

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

输出应该是这样的：

Cooking started at 30 deg
Minutes passed: 0, we are cooking at 40 deg
Minutes passed: 2, we are cooking at 50 deg
Minutes passed: 4, we are cooking at 60 deg
Minutes passed: 6, we are cooking at 70 deg
Minutes passed: 8, we are cooking at 80 deg
Minutes passed: 10, we are cooking at 90 deg
Minutes passed: 12, we are cooking at 100 deg
Minutes passed: 14, we are cooking at 110 deg
Minutes passed: 16, we are cooking at 120 deg
Minutes passed: 18, we are cooking at 120 deg
Minutes passed: 20, we are cooking at 120 deg
Minutes passed: 22, we are cooking at 120 deg
Minutes passed: 24, we are cooking at 120 deg
Total minutes of cooking is 25 min

Answer 1

在达到已知的最大值后，你想要保持循环似乎很奇怪。最简单的方法是将最大循环次数设置为<=16，因为您知道需要在那里结束。

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 16; min++) {

   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 16) {
       console.log("Total minutes of cooking is 25 min");
   }
}

或者，如果你必须持续25分钟，你只需要包括16分钟的测试并相应地设置temp：

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if(min >= 16) {
      // If we've arrived in this branch, at least 16 minutes of cooking has already happened
      temp = 120;  // Set temp to max
      console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   } else if (min % 2 === 0) {
       // If we've arrived in this branch, we must be less than 16 minutes in and 
       // we are on an even minute, so proceed as normal
       temp += 10;
       console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

Answer 2

如果您只是根据temp应用min的公式，则可以大大减少代码。使用Math.min可确保温度不会超过某个值。因为你每两分钟只打印一次，所以你可以让你的循环花费很多分钟。最后，由于25分钟的消息只发生一次，最后一次，最好放在循环之外：

console.log("Cooking started at 30 deg");
for (var min = 0; min <= 25; min+=2) {
   var temp = Math.min(120, 40 + min*5);
   console.log("Minutes passed: " + min + ", we are cooking at " + temp + " deg");
}
console.log("Total minutes of cooking is 25 min");

Answer 3

只需设置检查时间是否大于16分钟的条件，然后将temp设置为120.否则，将其递增5：

var temp = 30,
min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

   if (min >= 16) {
       temp = 120;
   } else {
       temp += 5;
   }

   if (min % 2 === 0) {
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + temp + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

此外，最好将日志记录和温度设置保存在单独的代码块中，以免事情变得太混乱。

Answer 4

如果我正确地阅读了您的问题，您希望在值{120}后停止修改temp。您有两个选项：break;或continue;。

break;将完全停止for循环，并且在您调用它之后它将停止循环。

continue;将跳过该迭代的其余循环。如果你想在120点后保留循环的其余部分，这就是你想要的那个。示例：

var temp = 30,
min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {

  if(temp >= 120) {
    continue;
    // or 'break;' if you're done with the entire loop.
  }

  if (min % 2 === 0) {
      temp += 10;
      console.log("Minutes passed: " + min + 
                ", we are cooking at " + temp + " deg");
  }

  if (min % 2 !== 0 && min === 25) {
      console.log("Total minutes of cooking is 25 min");
  }
}

没有彻底测试过，但你明白了。

Answer 5

检查增量变量temp后，简单使用中断。

＆＃13;

console.clear();
var temp = 30,
  min = 0;
console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {
  if (temp >= 120) {
    break;
  }

  if (min % 2 === 0) {
    temp += 10;
    console.log("Minutes passed: " + min +
      ", we are cooking at " + temp + " deg");
  }

  if (min % 2 !== 0 && min === 25) {
    console.log("Total minutes of cooking is 25 min");
  }
}

＆＃13;

Answer 6

您可以在console.log()内设置三元运算符条件，以最小化代码：

var temp = 30,
    min = 0;
    console.log("Cooking started at " + temp + " deg");

for (min = 0; min <= 25; min++) {
   if (min % 2 === 0) {
       temp += 10;
       console.log("Minutes passed: " + min + 
                    ", we are cooking at " + (temp>120?120:temp) + " deg");
   }

   if (min % 2 !== 0 && min === 25) {
       console.log("Total minutes of cooking is 25 min");
   }
}

说明：

(temp>120?120:temp)
// shorthand to
if (temp>120) { 120 } else { temp }

对for-loop

6 个答案: