我试图从下面的soap xml响应中返回ErrorReason。然而它一直空着。我不知道如何处理名称空间。
我希望返回" 指定的信封有重复的收件人。"
declare @xml xml =
(
'<soap:Envelope xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:wsa="http://schemas.xmlsoap.org/ws/2004/08/addressing" xmlns:wsse="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-secext-1.0.xsd" xmlns:wsu="http://docs.oasis-open.org/wss/2004/01/oasis-200401-wss-wssecurity-utility-1.0.xsd">
<soap:Header>
<wsa:Action>http://schemas.xmlsoap.org/ws/2004/08/addressing/fault</wsa:Action>
<wsa:MessageID>urn:uuid:b0c43031-35b9-40a1-a217-36491cfdd07c</wsa:MessageID>
<wsa:RelatesTo>urn:uuid:4871a441-ea1e-4f9b-953b-d3f426674597</wsa:RelatesTo>
<wsa:To>http://schemas.xmlsoap.org/ws/2004/08/addressing/role/anonymous</wsa:To>
<wsse:Security>
<wsu:Timestamp wsu:Id="Timestamp-c41a3e0c-317d-46e2-b203-6a0a43450313">
<wsu:Created>2017-08-31T18:11:00Z</wsu:Created>
<wsu:Expires>2017-08-31T18:16:00Z</wsu:Expires>
</wsu:Timestamp>
</wsse:Security>
</soap:Header>
<soap:Body>
<soap:Fault>
<faultcode>soap:Client</faultcode>
<faultstring>The specified envelope has duplicate recipients. </faultstring>
<faultactor>https://www.test.asmx</faultactor>
<detail>
<ErrorCode xmlns="missing in Web.Config">140</ErrorCode>
<ErrorReason xmlns="missing in Web.Config">The specified envelope has duplicate recipients.</ErrorReason>
</detail>
</soap:Fault>
</soap:Body>
</soap:Envelope>'
)
select x.value('ErrorReason[1]','VARCHAR(max)') from @xml.nodes('/*:Envelope/*:Body/detail') as X(x)
答案 0 :(得分:0)
您想要以下查询
select @xml.query('/*:Envelope/*:Body/*:Fault/*:detail/*:ErrorReason/text()')