Question

谷歌搜索了一段时间后，我认为我不能使用“枢轴”，因为它在Redshift上不可用，但我想也许周围有天才可以帮助我解决这个问题。 / p>

我想让整个结果表在左上角的单元格上旋转。

现在，我的查询如下：

SELECT pid,
COUNT(DISTINCT CASE WHEN colA = 'true' THEN id ELSE NULL END) as "cA",
COUNT(DISTINCT CASE WHEN colB = 'true' THEN id ELSE NULL END) as "cB",
COUNT(DISTINCT CASE WHEN colC = 'true' THEN id ELSE NULL END) as "cC",
COUNT(DISTINCT CASE WHEN colD = 'true' THEN id ELSE NULL END) as "cD",
FROM Data1.Table1 
WHERE date1 >= date(getdate()-7) and pid IS NOT NULL
group by pid

它给了我这张桌子

pid cA  cB  cC  cD
r1  A1  B1  C1  D1
r2  A2  B2  C2  D2
r3  A3  B3  C3  D3
r4  A4  B4  C4  D4

如何透视它以便我得到一个如下所示的表：

pid r1  r2  r3  r4
cA  A1  A2  A3  A4
cB  B1  B2  B3  B4
cC  C1  C2  C3  C4
cD  D1  D2  D3  D4

实际上，原始表比这个例子多了很多列并且不容易阅读。这就是为什么我想转动它并使它大部分是垂直的。

是否可以这样做？

根据要求，这里是数据的“样本”以及我当前查询从样本中提供的内容。

样品

id      date1       pid cA      cB      cC      cD
1000    9/6/2017    r1  true    false   true    false
1001    9/7/2017    r1  false   true    true    true
1001    9/5/2017    r3  true    false   true    false
1002    9/7/2017    r2  true    true    true    false
1003    9/1/2017    r4  false   false   false   true
1004    8/24/2017   r3  true    false   true    false
1002    9/7/2017    r2  false   false   true    false

查询结果

pid cA  cB  cC  cD
r1  1   1   2   1
r2  1   1   2   1
r3  2   0   2   0
r4  0   0   0   0

通缉结果

pid r1  r2  r3  r4
cA  1   1   2   0
cB  1   1   0   0
cC  2   2   2   0
cD  1   1   0   0

Answer 1

您可以使用UNION ALL以您想要的方式旋转它。

select 'cA' as pid
    , count(distinct case when ca is true and pid = 'r1' then id else null end) as r1
    , count(distinct case when ca is true and pid = 'r2' then id else null end) as r2
    , count(distinct case when ca is true and pid = 'r3' then id else null end) as r3
    , count(distinct case when ca is true and pid = 'r4' then id else null end) as r4
from table1
group by 1

union all

select 'cB' as pid
    , count(distinct case when cb is true and pid = 'r1' then id else null end) as r1
    , count(distinct case when cb is true and pid = 'r2' then id else null end) as r2
    , count(distinct case when cb is true and pid = 'r3' then id else null end) as r3
    , count(distinct case when cb is true and pid = 'r4' then id else null end) as r4
from table1
group by 1

union all

select 'cC' as pid
    , count(distinct case when cc is true and pid = 'r1' then id else null end) as r1
    , count(distinct case when cc is true and pid = 'r2' then id else null end) as r2
    , count(distinct case when cc is true and pid = 'r3' then id else null end) as r3
    , count(distinct case when cc is true and pid = 'r4' then id else null end) as r4
from table1
group by 1

union all

select 'cD' as pid
    , count(distinct case when cd is true and pid = 'r1' then id else null end) as r1
    , count(distinct case when cd is true and pid = 'r2' then id else null end) as r2
    , count(distinct case when cd is true and pid = 'r3' then id else null end) as r3
    , count(distinct case when cd is true and pid = 'r4' then id else null end) as r4
from table1
group by 1

order by 1

根据需要随意添加WHERE子句。

请记住，如果有更多的pid（r5，r6等），则需要手动添加它们。这不是很有效但我不认为Redshift还有另一种方式。

Answer 2

试试这个：

我在这里使用了纯粹的枢轴转换：

CREATE TABLE temp_table ( ids INT,A NVARCHAR(5),B NVARCHAR(5),C NVARCHAR(5),D NVARCHAR(5))
INSERT INTO temp_table VALUES (1,'A1','B1','C1','D1'), (2,'A2','B2','C2','D2'), (3,'A3','B3','C3','D3'),(4,'A4','B4','C4','D4'),(5,'A5','B5','C5','D5')
SELECT * FROM temp_table

DECLARE @temp_table_columns TABLE (id INT,col NVARCHAR(20))
DECLARE @result_val TABLE(id INT,value NVARCHAR(max))
INSERT INTO @temp_table_columns SELECT ORDINAL_POSITION id,COLUMN_NAME  FROM INFORMATION_SCHEMA.COLUMNS WHERE TABLE_NAME = N'temp_table'
DECLARE @initial_value NVARCHAR(MAX)='',@starter INT = (SELECT MAX(id) FROM @temp_table_columns),@initial INT = 0
WHILE(@initial<@starter)
BEGIN
DECLARE @rower NVARCHAR(20) = (SELECT col FROM @temp_table_columns WHERE id=@initial+1)
INSERT INTO @result_val EXEC ('SELECT '''+@initial+''', '+@rower+' FROM temp_table')
SET @initial_value = @initial_value + 
' UNION SELECT '+CONVERT(NVARCHAR,@initial)+' [id],'''+@rower+''' '+@rower +(SELECT ', '''+value+''' ['+value+']' 
FROM @result_val WHERE id=@initial FOR XML PATH(''))
SET @initial=@initial+1
END
IF EXISTS(SELECT 1 FROM INFORMATION_SCHEMA.TABLES WHERE TABLE_NAME='temp_table') DROP TABLE temp_table
SET @initial_value = 'SELECT * INTO temp_table FROM (' + SUBSTRING(@initial_value,8,LEN(@initial_value)) + ' ) A WHERE id<>0'
EXEC (@initial_value)
ALTER TABLE temp_table DROP COLUMN [id]
SELECT * FROM temp_table

您可以相应地修改它。：）

SQL如何在左上角的单元格中旋转整个表

2 个答案: