Question

我有3张桌子：

Category
+-------------+----------+
| category_id | name     |
+-------------+----------+
| 1           | Business |
+-------------+----------+
| 2           | Sport    |
+-------------+----------+
| 3           | Games    |
+-------------+----------+

News
+----+----------------------+
| id | title                |
+----+----------------------+
| 1  | Bitcoin Price        |
+----+----------------------+
| 2  | Sport                |
+----+----------------------+
| 3  | Electric flying cars |
+----+----------------------+

CatNews
+---------+--------+
| news_id | cat_id |
+---------+--------+
| 1       | 1      |
+---------+--------+
| 2       | 3      |
+---------+--------+
| 2       | 2      |
+---------+--------+

SELECT *, GROUP_CONCAT(cat.name) FROM news n JOIN CatNews c ON n.id = c.newsid JOIN category cat ON c.cat_id = cat.category_id GROUP BY n.id;

使用此功能，我收到

返回

id | title                | news_id | cat_id | name | GROUP_CONCAT(cat.name) 
2  | Electric flying cars |     2   |   3    | Sport | Sport, Games

问题出在我使用时：

SELECT *, GROUP_CONCAT(cat.name) FROM news n JOIN CatNews c ON n.id = c.newsid JOIN category cat ON c.cat_id = cat.category_id AND cat.name LIKE '%Games%' GROUP BY n.id

返回我：

id | title                | news_id | cat_id | name | GROUP_CONCAT(cat.name) 
2  | Electric flying cars |     2   |   3    | Games |   Games

如何使用LIKE查找事件但保留GROUP_CONCAT的值？

我想保留[运动，游戏]

Answer 1

我想你想要返回包含“游戏”的新闻项目。如果是这样，这是正确的逻辑：

SELECT n.*, GROUP_CONCAT(c.name)
FROM news n JOIN
     CatNews cn
     ON n.id = cn.newsid JOIN
     category c ON cn.cat_id = c.category_id
GROUP BY n.id
HAVING SUM(category_id = 'Games') > 0;

如何使用＆＃39; LIKE＆＃39;并保持加入值

1 个答案: