我尝试使用AND但它没有工作
这是原始代码
getAllFeeds(user_id_fk, start) {
let data = [user_id_fk, start]
// ---------this part here ------------------------------------------------------------
return this.database.executeSql("SELECT * FROM feed WHERE (user_id_fk) = (?) ORDER BY feed_id DESC LIMIT ?, 5", data).then((data) => {
// ------------------------------------------------------------------------------------
let feeds = [];
if (data.rows.length > 0) {
for (var i = 0; i < data.rows.length; i++) {
feeds.push({ feed_id: data.rows.item(i).feed_id, feed: data.rows.item(i).feed, user_id_fk: data.rows.item(i).user_id_fk, created: data.rows.item(i).created });
}
}
return feeds;
}, err => {
console.log('Error: ', err);
return [];
});
}
如何添加此内容?
SELECT DATETIME(created, '+8 hours') as `add8hours` FROM feed WHERE (user_id_fk) = (?) ORDER BY feed_id DESC;
当我使用最后一行时,结果将只显示日期时间而不显示其他列 这是表BTW
CREATE TABLE IF NOT EXISTS feed (
feed_id INTEGER PRIMARY KEY AUTOINCREMENT,
feed TEXT,
user_id_fk INTEGER,
created DATETIME DEFAULT CURRENT_TIMESTAMP
);
答案 0 :(得分:0)
如果要显示表中的某些特定列,则需要用逗号分隔它们。
例如(使用别名):SELECT COLUMN_1_NAME as ALIAS_COLUMN_1, COLUMN_2_NAME as ALIAS_COLUMN_2 FROM TABLE_NAME;
所以在你的情况下它应该是这样的:
SELECT DATETIME(created, '+8 hours') as add8hours, feed FROM feed WHERE (user_id_fk) = (?) ORDER BY feed_id DESC LIMIT ?, 5