Question

这是一款要求用户在3乘3网格上输入位置然后另一位用户尝试猜测该位置的游戏。调试错误时遇到问题。

这条线有什么问题？ Col=int(guess[1:])-1

在以下代码中？

当我尝试在repl.it中运行它时，它会返回以下错误。

回溯（最近一次呼叫最后一次）：文件＆＃34; python＆＃34;，第84行，in 文件＆＃34; python＆＃34;，第71行，在 init 中ValueError：无效对于带有基数10的int（）的文字：＆＃39;＆＃39;

#Creation of the grid and the user interface list
grid = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
turns=0
guess="x"
#Function to clear screen
def cls(): 
  print ("\n" * 100)

#Function to validate coordinate
def validate_entry():
  valid=False
  while valid==False:
    guess=input("Enter a location from A1 to C3: ")
    loc = guess.upper() #Use upper case
    row = guess[0:1]
    col = guess[1:2]
    if(row!="A" and row!="B" and row!="C") or (col!="1" and col!="2" and col!="3"):
      print("Your location is invalid.")
      print("")
      return False #not actually needed, but helps see what is happening
    else:
     valid=True
     return True
#Function to set the location of the treasure
def settingTreasure(grid):

    treasureSet=input("Set location by entering a location from A1 to C3: ")
    #Converting the letter into a coordinate in the list
    treasure_letter=str(treasureSet[:1])
    if treasure_letter in ["a", "A"]:
      locRow=0
    elif treasure_letter in ["b", "B"]:
      locRow=1
    elif treasure_letter in ["c", "C"]:
      locRow=2
    #Converting the number into a list coordinate
    locCol=int(treasureSet[1:])-1
    grid[locRow][locCol]=1

settingTreasure(grid)
cls()
#Displaying the user interface in a clean manner
def gameBoard():
  UI = [[0, 0, 0], [0, 0, 0], [0, 0, 0]]
  for i in range(0,len(UI)):
    print(UI[i])

gameBoard()

#The main loop that contains the game
def _init_(turns, guess):
  turns=turns+1
 #If the player exceeds three turns they lose
  if turns>3:
    print("Too many turns! You lose!")
    quit()

  #Prints number of turns
  print(" ")
  print("Turn " + str(turns))
  validate_entry()
  #Converting the letter into a coordinate in the list
  guess_letter=str(guess[:1])
  if guess_letter in ["a", "A"]:
    Row=0
  elif guess_letter in ["b", "B"]:
    Row=1
  elif guess_letter in ["c", "C"]:
    Row=2
  #Converting the number into a list coordinate
  Col=int(guess[1:])-1

  #Test to see if they guessed treasure location
  if grid[Row][Col]==1:
    print(" ")
    print("found treasure!")
    quit()
  else:
    print(" ")
    print("Treasure not here!")

#Loop for the main game
while True:
 _init_(turns, guess)

Answer 1

验证用户的输入后，您没有返回稍后要使用的值，因此猜测值保持为初始化代码时的“x”

尝试更改validate_entry函数和 init 函数

def validate_entry():
  valid=False
  while valid==False:
    guess=input("Enter a location from A1 to C3: ")
    loc = guess.upper() #Use upper case
    row = guess[0:1]
    col = guess[1:2]
    if(row!="A" and row!="B" and row!="C") or (col!="1" and col!="2" and col!="3"):
      print("Your location is invalid.")
      print("")
      return False #not actually needed, but helps see what is happening
    else:
     valid=True
     return guess


def _init_(turns):
  turns=turns+1
 #If the player exceeds three turns they lose
  if turns>3:
    print("Too many turns! You lose!")
    quit()

  #Prints number of turns
  print(" ")
  print("Turn " + str(turns))
  guess = validate_entry()
  #Converting the letter into a coordinate in the list
  guess_letter=str(guess[:1])
  if guess_letter in ["a", "A"]:
    Row=0
  elif guess_letter in ["b", "B"]:
    Row=1
  elif guess_letter in ["c", "C"]:
    Row=2
  #Converting the number into a list coordinate
  Col=int(guess[1:])-1

  #Test to see if they guessed treasure location
  if grid[Row][Col]==1:
    print(" ")
    print("found treasure!")
    quit()
  else:
    print(" ")
    print("Treasure not here!")

_init_(turns)

validate_entry函数现在返回猜测值，然后将其传递给函数调用中的 init 函数

附注：您可以在[“a”，“A”]中使用guess_letter.upper() == "A"代替guess_letter。 upper()有助于将字母转换为大写。但您可能希望在此之前检查guess_letter.isalpha()。我认为这种方式可能更容易，因为您只需要在此之后更改一个字符。另一种方法是在测试它是alpha

之后获取string.ascii_uppercase中字母的索引

ValueError：基数为10的int（）的无效文字：

1 个答案: