Question

如果a为1，b为2，c为3，我试图让程序计算每个单词的值，依此类推。我已经制作了大部分代码，但它不起作用。有人能给我一些建议吗？我刚刚开始学习python，所以你能尽可能详细吗？谢谢。

__author__ = "Anthony Chen"
__copyright__ = "Copyright (C) 2017 Anthony Chen"
__license__ = "Public Domain"
__version__ = "1.0"

output = ('None')
worth = {'a':1,
'b':2,
'c':3,
'd':4,
'e':5,
'f':6,
'g':7,
'h':8,
'i':9,
'j':10,
'k':11,
'l':12,
'm':13,
'n':14,
'o':16,
'q':17,
'r':18,
's':19,
't':20,
'u':21,
'v':22,
'w':23,
'x':24,
'y':25,
'z':26,
}


def findworth():
    for char in wordlist:
        if char in wordlist:
           output = (worth[char])
           wordlist.replace(output) 
        elif worth[char] == False:
            output = (None)

while True:
    output = (None)
    wordlist = []
    word = input(str("Find out how many cents your word is worth. Please enter your word:"))
    word = word.lower()
    wordlist = list(word)
    wordlist = findworth()
    output = sum(wordlist)
    print("Your word's value is:")
    print (output)
    print('.')

这是我运行时显示的内容：

**Find out how many cents your word is worth. Please enter your word:Bananas
Traceback (most recent call last):
  File "C:/Anthony/School/__CentsWord/WordWorth.py", line 49, in <module>
    wordlist = findworth()
  File "C:/Anthony/School/__CentsWord/WordWorth.py", line 39, in findworth
    wordlist.replace(output)
AttributeError: 'list' object has no attribute 'replace'**

Answer 1

对于避免使用更高级技术的解决方案：

worth = {
    'a':1, 'b':2, 'c':3, 'd':4, 'e':5, 'f':6, 'g':7,
    'h':8, 'i':9, 'j':10, 'k':11, 'l':12, 'm':13, 'n':14,
    'o':15, 'q':17, 'r':18, 's':19, 't':20, 'u':21, 
    'v':22, 'w':23, 'x':24, 'y':25, 'z':26}

def findworth(word):
    total = 0
    for char in word:
        if char in worth:
            total += worth[char]
    return total

print("Find out how many cents your word is worth.")

while True:
    word = input("Please enter your word: ").lower()
    print("Your word's value is:", findworth(word))

按如下方式输出：

Find out how many cents your word is worth.
Please enter your word: abc
Your word's value is: 6
Please enter your word: hello
Your word's value is: 53

注意： worth目前缺少p，o值不正确，应该是：

worth = {
    'a':1, 'b':2, 'c':3, 'd':4, 'e':5, 'f':6, 'g':7,
    'h':8, 'i':9, 'j':10, 'k':11, 'l':12, 'm':13, 'n':14,
    'o':15, 'p':16, 'q':17, 'r':18, 's':19, 't':20, 'u':21, 
    'v':22, 'w':23, 'x':24, 'y':25, 'z':26}

Answer 2

根据你的解决方案（它不是很好的imo，会提供更好的解决方案）

def findworth():
    for i,char in enumerate(wordlist):
        if char in worth:
            output = (worth[char])
            wordlist[i] = (output) 
        else:
            output = (None)

while True:
    output = (None)
    wordlist = []
    word = input(str("Find out how many cents your word is worth. Please enter your word:"))
    word = word.lower()
    wordlist = list(word)
    findworth()
    output = sum(wordlist)
    print("Your word's value is:")
    print (output)
    print('.')

减少冗余的更好解决方案

while True:
    word = input(str("Find out how many cents your word is worth. Please enter your word:"))
    word = word.lower()
    output = 0 # set initial value
    for char in word: # iterate string for each character
        if char in worth: # check if its a valid char
            output += worth[char] # same as output = output + worth[char]

    print("Your word's value is:")
    print (output)
    print('.')

Python的字符串已经可以迭代，所以你不必把它变成一个列表：）

Answer 3

我的第一个评论是，用于生成worth的方法很长，很容易出错，事实上，您似乎忘记了'p'而是使用了{{1} }}。您可以使用字典理解生成您的价值清单：

'o':16

这可以通过循环数字1..26，并将worth = {chr(x+96):x for x in range(1,27)}转换为字符（使用ASCII表来查看97是n + 96，98是'a'等等然后，将此字符用作值的键。

接下来，我们可以为单词中的每个字符生成一个值列表：

'b'

这会给我们word = "hello" scores = [worth[c] for c in word]。

最后，您可以调用scores == [8, 5, 12, 12, 5]函数来添加列表中的所有值：

sum

返回sum(scores)。

你可以将它们组合成一个函数来获取：

或者，这可以在1行上完成：

def get_word_score(word):
    worth = {chr(x+96):x for x in range(1,27)}
    scores = [worth[c] for c in word]
    return sum(scores)

sum([ord(c)-96 for c in word])与ord相反，它返回给定字符的ASCII值。

使用chr一词sum([ord(c)-96 for c in word])的演练。第一步是将每个角色放入一个列表中：

'hello'

接下来将每个字符转换为ASCII值：

>>> [c for c in 'hello']
['h', 'e', 'l', 'l', 'o']

接下来，通过减去96：

将每个ASCII值转换为字母位置

>>> [ord(c) for c in 'hello']
[104, 101, 108, 108, 111]

最后总结：

>>> [ord(c)-96 for c in 'hello']
[8, 5, 12, 12, 15]

您的代码功能是：

>>> sum([ord(c)-96 for c in 'hello'])
52

如何制作程序来计算每个单词的价值

3 个答案: