我在java代码中收到一条奇怪的错误消息... 我正在尝试制作一个可以将两个数字组合在一起的简单计算器,但它不起作用,因为我是Java的新手......这是错误代码:
package testing;
import java.util.Scanner;
public class Test1 {
public static Scanner scan;
public static void main(String[] args) {
scan = new Scanner(System.in);
int n1 = 0;
System.out.print("What would you like to add");
System.out.print(scan.nextInt(n1) + "You have selected" + scan.nextInt(n1));
int n2 = 0;
System.out.print(scan.nextInt(n2) + "You have selected" + scan.nextInt(n2));
System.out.print("Calculation=" + n1+n2);
}
}
我的代码是
Jenkins
我无法弄清楚为什么它不起作用而且它正在我的头脑中 - .- 我是Java的新手,所以如果你能帮助我,我会非常感激:)
答案 0 :(得分:1)
我认为你应该尝试不同的方法,这样的东西更具可读性,而且在我看来,如果你开始的话,更容易使用。
public class Main {
public static void main(String[] args) {
Scanner scan ;
scan = new Scanner(System.in);
System.out.println("What would you like to add");
int n1 = scan.nextInt();
System.out.println( "You have selected" + n1);
int n2 = scan.nextInt();
System.out.println( "You have selected" + n2);
int calculation= n1+n2;
System.out.println("Calculation=" + calculation);
}
答案 1 :(得分:0)
我相信这就是你要做的事情:
public class Testing {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
System.out.println("What would you like to add");
int n1 = scan.nextInt();
System.out.println("You have selected" + n1);
int n2 = scan.nextInt();
System.out.println("You have selected" + n2);
System.out.println("Calculation=" + (n1 + n2));
scan.close();
}
}
有几点需要注意:
需要将nextInt()分配给变量(不传递给它)
n1 + n2需要放在paranthesis(n1 + n2)中,否则将被处理为String。