Question

我发布了一个我以前以某种方式表示数据的问题，经过2个帖子后，我能够获得足够的信息来实现我需要的是带有动态列的数据透视表。

我已经能够创建一个具有很好效果的静态数据透视表，但对于严肃的报告，它们是无用的。以下是我到目前为止所做的事情：

select `title` as `Payment Method`,
  sum(case when MONTH(t1.`month_payment`) = 1 then amount else 0 end) Jan,
  sum(case when MONTH(t1.`month_payment`) = 2 then amount else 0 end) Feb,
  sum(case when MONTH(t1.`month_payment`) = 3 then amount else 0 end) Mar,
  sum(case when MONTH(t1.`month_payment`) = 4 then amount else 0 end) Apr,
  sum(case when MONTH(t1.`month_payment`) = 5 then amount else 0 end) May,
  sum(case when MONTH(t1.`month_payment`) = 6 then amount else 0 end) Jun,
  sum(case when MONTH(t1.`month_payment`) = 7 then amount else 0 end) Jul,
  sum(case when MONTH(t1.`month_payment`) = 8 then amount else 0 end) Aug,
  sum(case when MONTH(t1.`month_payment`) = 9 then amount else 0 end) Sep,
  sum(case when MONTH(t1.`month_payment`) = 10 then amount else 0 end) Oct,
  sum(case when MONTH(t1.`month_payment`) = 11 then amount else 0 end) Nov,
  sum(case when MONTH(t1.`month_payment`) = 12 then amount else 0 end) `Dec`

from record_payment t1
join setting_payment_method ON
setting_payment_method.id = t1.method_id
where `month_payment` >= '$date_from'
  and `month_payment` <= '$date_to'
group by title with rollup

这可以在1月到12月之间给我一个静态报告，但问题是如果用户从2015年1月到2017年12月进行搜索，该表将汇总并汇总2015年1月，2016年和2017年全部显示在1月份对于错误的用户。

我还为年度报告制作了一个静态轴：

select `title` as `Payment Method`,
  sum(case when YEAR(t1.`month_payment`) = 2013 then amount else 0 end) `2013`,
  sum(case when YEAR(t1.`month_payment`) = 2014 then amount else 0 end) `2014`,
  sum(case when YEAR(t1.`month_payment`) = 2015 then amount else 0 end) `2015`,
  sum(case when YEAR(t1.`month_payment`) = 2016 then amount else 0 end) `2016`,
  sum(case when YEAR(t1.`month_payment`) = 2017 then amount else 0 end) `2017`

from record_payment t1
join setting_payment_method ON
setting_payment_method.id = t1.method_id
where `month_payment` >= '$date_from'
  and `month_payment` <= '$date_to'
group by title with rollup

但有时您需要能够在很长一段时间内（例如12岁以上）为您提供年度分类的报告，以便您可以看到趋势。

我尝试自动转动并不是那么成功：

SET @sql = NULL;
SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'sum(case when month_payment = ''',
      month_payment,
      ''' then amount end) AS `',
      month_payment,
      '`'
    )
  ) INTO @sql
FROM  record_payment;

SET @sql = CONCAT('SELECT `title` as `Payment Method`, ', @sql, ' FROM record_payment t1
join setting_payment_method ON
setting_payment_method.id = t1.method_id
where `month_payment` >= '$date_from'
  and `month_payment` <= '$date_to'
group by title with rollup');
PREPARE stmt FROM @sql;
EXECUTE stmt;
DEALLOCATE PREPARE stmt;

感谢任何帮助。

Answer 1

我猜你的month_payment列是DATE（顺便说一下，当你提出SQL问题时应该发布SHOW CREATE TABLE，所以我们不必猜测）。

但是您的第一个查询并未将其格式化为年/月。也不限制日期范围。

SELECT
  GROUP_CONCAT(DISTINCT
    CONCAT(
      'SUM(CASE WHEN EXTRACT(YEAR_MONTH FROM month_payment) = ',
      EXTRACT(YEAR_MONTH FROM month_payment),
      ' THEN AMOUNT END) AS `',
      EXTRACT(YEAR_MONTH FROM month_payment),
      '`'
    )
  ) INTO @sql
FROM record_payment
WHERE month_payment BETWEEN ? AND ?

请参阅https://dev.mysql.com/doc/refman/5.7/en/date-and-time-functions.html#function_extract

尽管有Barmar的建议，但没有理由把它放在存储过程中。你用PHP标记了你的问题，你可以用PHP做到这一点：

<?php

...get a PDO connection...

$sql = "
    SELECT
      GROUP_CONCAT(DISTINCT
        CONCAT(
          'SUM(CASE WHEN EXTRACT(YEAR_MONTH FROM month_payment) = ',
          EXTRACT(YEAR_MONTH FROM month_payment),
          ' THEN AMOUNT END) AS `',
          EXTRACT(YEAR_MONTH FROM month_payment),
          '`'
        )
      ) AS `pivot_columns`
    FROM record_payment
    WHERE month_payment BETWEEN ? AND ?
";
$stmt = $pdo->prepare($sql);
$date_from = '2017-01-01';
$date_to   = '2017-08-01';
$stmt->execute([$date_from, $date_to]);
$row = $stmt->fetch();
$stmt->closeCursor();
$pivot_columns = $row['pivot_columns'];

$sql = "
    SELECT title AS `Payment Method`, {$pivot_columns}
    FROM record_payment t1
    JOIN setting_payment_method spm ON spm.id = t1.method_id
    WHERE month_payment BETWEEN ? AND ?
    GROUP BY title WITH ROLLUP
";
echo $sql;
$stmt = $pdo->prepare($sql);
$stmt->execute([$date_from, $date_to]);
$results = $stmt->fetchAll();
$stmt->closeCursor();

print_r($results);

使用动态列透视MySQL表

1 个答案: