我有一个对象数组,如下所示:
data = [
{
title: 'John Doe',
departments: [
{ name: 'Marketing', slug: 'marketing'},
{ name: 'Sales', slug: 'sales'},
{ name: 'Administration', slug: 'administration'},
]
},
{
title: 'John Doe Junior',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Sales', slug: 'sales'},
]
},
{
title: 'Rick Stone',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Marketing', slug: 'marketin'},
]
},
]
如何迭代每个对象的departments数组并创建新的数组,我将按部门对员工进行排序,以便最终结果如下:
operations = [
{
title: 'John Doe Junior',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Sales', slug: 'sales'},
]
},
{
title: 'Rick Stone',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Marketing', slug: 'marketin'},
]
},
]
marketing = [
{
title: 'John Doe',
departments: [
{ name: 'Marketing', slug: 'marketing'},
{ name: 'Sales', slug: 'sales'},
{ name: 'Administration', slug: 'administration'},
]
},
{
title: 'Rick Stone',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Marketing', slug: 'marketin'},
]
},
]
动态创建这种数组的方法是什么?
更新
我尝试使用答案中的建议提出解决方案,在那里我将动态创建一个包含部门对象的数组,这些对象将有一系列员工:
const isInDepartment = departmentToCheck => employer => employer.departments.find(department => department.slug == departmentToCheck);
var departments = [];
function check(departments, name) {
return departments.some(object => name === object.department);
}
employees.forEach((employee) => {
employee.departments.forEach((department) => {
let found = check(departments, department.slug);
if (!found) {
departments.push({ department: department.slug });
}
});
});
departments.forEach((department) => {
// push an array of employees to each department
//employees.filter(isInDepartment(department));
});
但是,我不知道如何将员工阵列推送到我最后循环的数组中的对象? 这是fiddle。
答案 0 :(得分:1)
这个怎么样?我使用Array.protoype.filter
操作,并使用高阶函数(在这种情况下是一个返回函数的函数)来创建谓词(返回布尔值的函数),该函数将检查员工是否在特定部门。我在代码中添加了一些(希望)澄清的评论。
修改:使用您提供的新代码和上下文this JSFiddle demo显示它如何协同工作。
const employees = [
{
title: 'John Doe',
departments: [
{ name: 'Marketing', slug: 'marketing'},
{ name: 'Sales', slug: 'sales'},
{ name: 'Administration', slug: 'administration'}
]
},
{
title: 'John Doe Junior',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Sales', slug: 'sales'}
]
},
{
title: 'Rick Stone',
departments: [
{ name: 'Operations', slug: 'operations'},
{ name: 'Marketing', slug: 'marketin'}
]
}
];
// given a department, this returns a function that checks
// whether an employee is in the specified department
// NOTE: the "find" returns the found object (truthy)
// or undefined (falsy) if no match was found.
const isInDepartment =
departmentToCheck =>
employee => employee.departments.find(dep => dep.name == departmentToCheck);
const employeesInMarketing = employees.filter(isInDepartment('Marketing'));
const employeesInOperations = employees.filter(isInDepartment('Operations'));
console.log('Employees in marketing', employeesInMarketing);
console.log('Employees in operations', employeesInOperations);