我的代码应该比较两个保存为字典的向量(两个pickle文件),并将结果保存到pickle文件中。这工作但非常缓慢。对于一个比较结果,我等待7:2分钟。因为我有很多视频(正好是2033年),这个编程将持续大约10天。这太长了。如何加速Python 2.7的代码?
import math
import csv
import pickle
from itertools import izip
global_ddc_file = 'E:/global_ddc.p'
io = 'E:/AV-Datensatz'
v_source = ''
def dot_product(v1, v2):
return sum(map(lambda x: x[0] * x[1], izip(v1, v2))) # izip('ABCD', 'xy') --> Ax By
def cosine_measure(v1, v2):
prod = dot_product(v1, v2)
len1 = math.sqrt(dot_product(v1, v1))
len2 = math.sqrt(dot_product(v2, v2))
if (len1 * len2) <> 0:
out = prod / (len1 * len2)
else: out = 0
return out
def findSource(v):
v_id = "/"+v[0].lstrip("<http://av.tib.eu/resource/video").rstrip(">")
v_source = io + v_id
v_file = v_source + '/vector.p'
source = [v_id, v_source, v_file]
return source
def getVector(v, vectorCol):
with open (v, 'rb') as f:
try:
vector_v = pickle.load(f)
except: print 'file couldnt be loaded'
tf_idf = []
tf_idf = [vec[1][vectorCol] for vec in vector_v]
return tf_idf
def compareVectors(v1, v2, vectorCol):
v1_source = findSource(v1)
v2_source = findSource(v2)
V1 = getVector(v1_source[2], vectorCol)
V2 = getVector(v2_source[2], vectorCol)
sim = [v1_source[0], v2_source[0], cosine_measure(V1, V2)]
return sim
#with open('videos_av_portal_cc_3.0_nur2bspStanford.csv', 'rb') as dataIn:
with open('videos_av_portal_cc_3.0_vollstaendig.csv', 'rb') as dataIn:
#with open('videos_av_portal_cc_3.0.csv', 'rb') as dataIn:
try:
reader = csv.reader(dataIn)
v_source = []
for row in reader:
v_source.append(findSource(row))
#print v_source
for one in v_source:
print one[1]
compVec = []
for another in v_source:
if one <> another:
compVec.append(compareVectors(one, another, 3))
compVec_sort = sorted(compVec, key=lambda cosim: cosim[2], reverse = True)
# save vector file for each video
with open (one[1] + '/compare.p','wb') as f:
pickle.dump(compVec_sort,f)
finally:
dataIn.close()
答案 0 :(得分:0)
将代码分为两部分: 1.在向量中加载字典 2.使用多进程multiprocess example比较2个词典 3.根据内存可用性同时启动进程,并在8分钟后结束进程。然后更新第3个字典。 4.然后重新启动下一组数据的过程,按照步骤3继续直到字典长度。
这可以减少总周转时间。 如果您需要代码,请告诉我。