Question

我使用Xpath 1.0 Expression来查询XML文档。我的目标是将所有选定的节点输出到Jaspersoft报告中，该报告显示一个新页面以及每个Uid的相应数据。

这是我简化的XML文档片段：

<?xml version="1.0" encoding="UTF-8"?>
<root>
    <modules>
        <Operation>
            <Operation>
                <wellUid lookupLabel="Well992454">cf1</wellUid>
            </Operation>
        </Operation>
        <RigInformation>
            <RigInformation>
                <rigName>RigName12345</rigName>
                <rigInformationUid>rig005</rigInformationUid>
                <rigManager lookupLabel="Manager554">554</rigManager>
            </RigInformation>
            <RigInformation>
                <rigName>RigName4578945</rigName>
                <rigInformationUid>rig001</rigInformationUid>
                <rigManager lookupLabel="Manager2254879">2254</rigManager>
            </RigInformation>
        </RigInformation>       
        <Well>
            <Well>
                <wellUid>cf1</wellUid>
                <wellName>Name 1</wellName>
            </Well>
            <Well>
                <wellUid>cf2</wellUid>
                <wellName>Name 2</wellName>
            </Well>
        </Well>
        <ReportDaily>
            <ReportDaily>
                <wellUid>cf1</wellUid>
                <rigInformationUid>rig001</rigInformationUid>
            </ReportDaily>
        </ReportDaily>
    </modules>
</root>

我试图整理出一个显示wellUid下所有信息的XPath表达式。所以，如果有一个井＆＃34; 001＆＃34;和一个井＆＃34; 002＆＃34;，然后应该只有两行返回来自Well，RigInformation，Operation和ReportDaily的所有信息。

RigInformation没有wellUid，但有一个rigInformationUid，ReportDaily也有。

这是我迄今为止尝试的查询......

//ReportDaily/ReportDaily[wellUid = //Well/Well/wellUid] | //RigInformation/RigInformation[wellUid = //Well/Well/wellUid] | //Operation/Operation[wellUid = //Well/Well/wellUid] | //Well/Well[wellUid]

和

//Well/Well[wellUid and //ReportDaily/ReportDaily[wellUid = //Well/Well/wellUid and //Operation/Operation[wellUid = //Well/Well/wellUid and //RigInformation/RigInformation[rigInformationUid = //ReportDaily/ReportDaily/rigInformationUid]]]]

非常感谢任何帮助。

Answer 1

这应该让你开始，因为你迭代了给定的井＆＃39;

root/modules/*/*[descendant::wellUid/text() = //Well/Well[1]/wellUid/text()] | 
root/modules/*/*[descendant::rigInformationUid/text() = //descendant::rigInformationUid[preceding-sibling::wellUid/text() = //Well/Well[1]/wellUid/text()]/text()]

XPath多个节点

1 个答案: