Hay我在从createElement函数中排序div时遇到问题。
问题: 我从数据库项创建div,这些数据项在行中对齐(最后一项)
我想要的是什么: 以反方向显示项目。添加到数据库中的最新项目应显示为流中的第一项(如facebook上的新闻流)。
问题: 如何更改div的加载/创建方向?
此外,我想到了一种技术,可以为每个创建的div设置个人ID,以便稍后按ID排序(Id可以是正在进行的数字)。 我找到了这个,但它不起作用,而我没有增加ID号:Javascript create divs with different ids
我知道stackoverflow上有很多这样的问题,之前我尝试了几个,但我的问题没有成功。
查看我的代码:
//create firebase reference
var dbRef = new Firebase("….com/");
var contactsRef = dbRef.child('contacts')
//load all contacts
contactsRef.on("child_added", function(snap) {
//console.log(snap.val())
snap.forEach(function(childSnapshot) {
var key = childSnapshot.key();
var childData = childSnapshot.val();
var divCount = 0;
//create divs from database-elements
var card = document.createElement('div');
card.id = 'div'+divCount;
card.setAttribute('class', 'linkprev');
document.body.appendChild(card);
var cardtitle = document.createElement('div');
cardtitle.setAttribute('class', 'cardtitle');
cardtitle.innerHTML = childData;
card.appendChild(cardtitle);
document.guteUrls.execute();
divCount++;
console.log(event);
//linkify plugin to convert div-elements (strings) to hyperlinks
$('div').linkify();
$('#sidebar').linkify({
target: "_blank"
});
});
});
//save contact
document.querySelector(".addValue").addEventListener("click", function( event ) {
event.preventDefault();
if( document.querySelector('#url').value != '' && document.querySelector('#url').value.charAt(0) == "h" && document.querySelector('#url').value.charAt(3) == "p"){
contactsRef.push({
name: document.querySelector('#url').value,})
contactForm.reset();}
else {
alert('Oops, seems like an error…');
}
}, false);
<!DOCTYPE html>
<html lang="en">
<head>
<meta charset="utf-8">
<meta http-equiv="X-UA-Compatible" content="IE=edge">
<meta name="viewport" content="width=device-width, initial-scale=1">
<!-- The above 3 meta tags *must* come first in the head; any other head content must come *after* these tags -->
<title>frontendpublishing-test</title>
<!-- Latest compiled and minified CSS -->
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/css/bootstrap.min.css">
<link rel="stylesheet" href="http://cdn.embed.ly/jquery.preview-0.3.2.css" />
<link href="css/flexboxgrid.min.css" rel="stylesheet">
<style type="text/css">
#contacts p,
#contacts p.lead{
margin: 0;
}
</style>
</head>
<body>
<div class="container">
<h1>Titel h1</h1>
<hr/>
<div class="row">
<div class="col-md-6">
<form method="post" name="contactForm">
<div class="form-group">
<input id="url" type="url" required name="url" placeholder="share a good article/blog/topic" class="input">
<button type="submit" class="btn btn-primary addValue">Submit</button>
</form>
<!-- <script>
$document.ready(function){
document.getElementsByClassName('linkified');
{console.log("linkified")};
};
</script>
-->
<!-- jQuery (necessary for Bootstrap's JavaScript plugins) -->
<script src="https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js"></script>
<!-- Latest compiled and minified Bootstrap -->
<script src="https://maxcdn.bootstrapcdn.com/bootstrap/3.3.4/js/bootstrap.min.js"></script>
<!-- Include Firebase Library -->
<script src="https://cdn.firebase.com/js/client/2.2.3/firebase.js"></script>
<!-- Contacts Store JavaScript -->
<script src="script.js"></script>
<script src="linkify.min.js"></script>
<script src="linkify-jquery.min.js"></script>
<link rel="stylesheet" href="style.css" type="text/css" media="screen" />
<script async src="https://guteurls.de/guteurls.js"
selector='.linkprev'
gif="http://loading.io/assets/img/default-loader.gif"
callback-a="(function(jqueryElement,url,$){console.log('url:'+url)})"
callback="(function($){console.log('finished')})"
init="(function($){console.log('JS will start to search URLs now')})"
></script>
</body>
</html>
感谢您的帮助:)
答案 0 :(得分:0)
1.为什么不从db中查询它们的后代? :))
2
card.childNodes.length
? card.insertBefore(cardtitle, card.childNodes[0])
: card.appenChild(cardtitle);
答案 1 :(得分:0)
因为你使用的是jquery而不是
document.body.appendChild(card);
使用
$('body').prepend($(card))
您可以使用要添加它们的ID标记该区域,以便它不会插入到文档的顶部,如
$('#elementid').prepend($(card))