Question

生成月份＆amp; PHP中两个日期的年份数组

我从表单中两个 MM/YYYY 例如：

$start = "2/2016";
$end = "11/2017"

我需要所有月份和年份的输出像这样在php

$monthArray = Array ( 
                 [0] => 2 
                 [1] => 3 
                 [2] => 4 
                 [3] => 5 
                 [4] => 6 
                 [5] => 7 
                 [6] => 8 
                 [7] => 9 
                 [8] => 10 
                 [9] => 11 
                 [10] => 12 
                 [11] => 1 
                 [12] => 2 
                 [13] => 3 
                 [14] => 4 
                 [15] => 5 
                 [16] => 6 
                 [17] => 7 
                 [18] => 8 
                 [19] => 9 
                 [20] => 10 
                 [21] => 11 
            );

$yearArray = Array ( 
                 [0] => 2016 
                 [1] => 2016 
                 [2] => 2016 
                 [3] => 2016 
                 [4] => 2016 
                 [5] => 2016 
                 [6] => 2016 
                 [7] => 2016 
                 [8] => 2016 
                 [9] => 2016 
                 [10] => 2016 
                 [11] => 2017 
                 [12] => 2017 
                 [13] => 2017 
                 [14] => 2017 
                 [15] => 2017 
                 [16] => 2017 
                 [17] => 2017 
                 [18] => 2017 
                 [19] => 2017 
                 [20] => 2017 
                 [21] => 2017 
            );

功能会更好。请帮忙。提前致谢

Answer 1

如果您想使用日期时间，您可以这样做：

SELECT ( (SELECT SUM(qty_claimed) As total_items_claimed
          FROM so_claim_item
          WHERE sales_order_id = 1
         ) =
         (SELECT SUM(quantity) As total_items_ordered
          FROM sales_order_item
          WHERE sales_order_id = 1
         )
       ) as is_same;

示例：http://sandbox.onlinephpfunctions.com/code/8bfa8cc9481aa8a13d83f62d9c1c6c7927654842

Answer 2

<?php
$start = "2/2016";
$end = "11/2017";

$start = explode('/', $start);
$end = explode('/', $end);

$d1 = strtotime($start[1] . '-' . $start[0] . '-01');
$d2 = strtotime($end[1] . '-' . $end[0] . '-01');
$min_date = min($d1, $d2);
$max_date = max($d1, $d2);

$month = [];
$year = [];
while (($min_date = strtotime("+1 MONTH", $min_date)) <= $max_date) {
    $month[] = date('m',$min_date);
    $year[] = date('Y',$min_date);
}
print_r($month);
print_r($year);

Answer 3

这应该比现有的答案更快，使用更少的内存，因为它不依赖于日期对象的创建和操作（特别是将字符串解析为日期对象）：

/**
 * Takes start and end date string in format 'mm/yyyy' along with a $months and $years
 * arrays; modifies the arrays in place to add all months and years between the dates
 */
function listMonthsAndYears($start, $end, &$months, &$years) {

  list($startM, $startY) = array_map('intval', explode('/',$start));
  list($endM, $endY)     = array_map('intval', explode('/',$end));
  $m = $startM;
  $y = $startY;

  while($endY > $y || ($endY === $y && $endM >= $m) ){
    $months[]= $m;
    $years[] = $y;
    $m++;
    if($m > 12){ // loop to the next year
      $m = 1;
      $y++;
    }
  }
}

用法：

$start = '2/2016';
$end = '11/2017';
listMonthsAndYears($start, $end, $months, $years);

Live demo

生成月份和时间PHP中两个日期的年份数组

3 个答案: