如何在VBScript中将项添加到现有数组?
是否有一个VBScript等同于Javascript中的push函数?
即
myArray有三个项目,“苹果”,“橘子”和“香蕉”,我想在阵列的末尾添加“西瓜”。
答案 0 :(得分:60)
在VBScript中,数组不是很动态。您必须使用ReDim Preserve语句来扩展现有数组,以便它可以容纳额外的项目:
ReDim Preserve yourArray(UBound(yourArray) + 1)
yourArray(UBound(yourArray)) = "Watermelons"
答案 1 :(得分:10)
有几种方法,不包括自定义COM或ActiveX对象
通过下面的代码,我发现Redim Preserve最快54000以下,Dictionary最快从54000到690000,Array List最快超过690000.由于排序和数组转换,我倾向于使用ArrayList进行推送德尔>
user326639提供了FastArray,这是最快的。
字典对于搜索值和返回索引(即字段名称),或用于分组和聚合(直方图,组和添加,组和连接字符串,组和推送子数组)非常有用。在对键进行分组时,为case in / sensitivity设置CompareMode,并在“add”-ing之前检查“exists”属性。
Redim不会为一个数组节省太多时间,但它对数组字典很有用。
'pushtest.vbs
imax = 10000
value = "Testvalue"
s = imax & " of """ & value & """"
t0 = timer 'ArrayList Method
Set o = CreateObject("System.Collections.ArrayList")
For i = 0 To imax
o.Add value
Next
s = s & "[AList " & FormatNumber(timer - t0, 3, -1) & "]"
Set o = Nothing
t0 = timer 'ReDim Preserve Method
a = array()
For i = 0 To imax
ReDim Preserve a(UBound(a) + 1)
a(UBound(a)) = value
Next
s = s & "[ReDim " & FormatNumber(timer - t0, 3, -1) & "]"
Set a = Nothing
t0 = timer 'Dictionary Method
Set o = CreateObject("Scripting.Dictionary")
For i = 0 To imax
o.Add i, value
Next
s = s & "[Dictionary " & FormatNumber(timer - t0, 3, -1) & "]"
Set o = Nothing
t0 = timer 'Standard array
Redim a(imax)
For i = 0 To imax
a(i) = value
Next
s = s & "[Array " & FormatNumber(timer - t0, 3, -1) & "]" & vbCRLF
Set a = Nothing
t0 = timer 'Fast array
a = array()
For i = 0 To imax
ub = UBound(a)
If i>ub Then ReDim Preserve a(Int((ub+10)*1.1))
a(i) = value
Next
ReDim Preserve a(i-1)
s = s & "[FastArr " & FormatNumber(timer - t0, 3, -1) & "]"
Set a = Nothing
MsgBox s
' 10000 of "Testvalue" [ArrayList 0.156][Redim 0.016][Dictionary 0.031][Array 0.016][FastArr 0.016]
' 54000 of "Testvalue" [ArrayList 0.734][Redim 0.672][Dictionary 0.203][Array 0.063][FastArr 0.109]
' 240000 of "Testvalue" [ArrayList 3.172][Redim 5.891][Dictionary 1.453][Array 0.203][FastArr 0.484]
' 690000 of "Testvalue" [ArrayList 9.078][Redim 44.785][Dictionary 8.750][Array 0.609][FastArr 1.406]
'1000000 of "Testvalue" [ArrayList 13.191][Redim 92.863][Dictionary 18.047][Array 0.859][FastArr 2.031]
答案 2 :(得分:9)
为您的复制和粘贴轻松
' add item to array
Function AddItem(arr, val)
ReDim Preserve arr(UBound(arr) + 1)
arr(UBound(arr)) = val
AddItem = arr
End Function
像这样使用
a = Array()
a = AddItem(a, 5)
a = AddItem(a, "foo")
答案 3 :(得分:4)
从上面稍微改变FastArray:
'pushtest.vbs
imax = 10000000
value = "Testvalue"
s = imax & " of """ & value & """"
t0 = timer 'Fast array
a = array()
ub = UBound(a)
For i = 0 To imax
If i>ub Then
ReDim Preserve a(Int((ub+10)*1.1))
ub = UBound(a)
End If
a(i) = value
Next
ReDim Preserve a(i-1)
s = s & "[FastArr " & FormatNumber(timer - t0, 3, -1) & "]"
MsgBox s
如果我们确切地知道它何时发生变化,那么在for的每个周期中检查UBound(a)
是没有意义的。
我已更改它,以便它在for开始之前检查UBound(a)
,然后仅在每次调用ReDim
时检查
在我的计算机上,旧方法需要7.52秒才能获得1000万像素。
新方法花费5.29秒,同时也是1000万的imax,这意味着性能提升超过20%(对于1000万次尝试,显然这个百分比与尝试次数有直接关系)
答案 4 :(得分:0)
这有些迟到但无论如何也有些棘手
dim arrr
arr= array ("Apples", "Oranges", "Bananas")
dim temp_var
temp_var = join (arr , "||") ' some character which will not occur is regular strings
if len(temp_var) > 0 then
temp_var = temp_var&"||Watermelons"
end if
arr = split(temp_var , "||") ' here you got new elemet in array '
for each x in arr
response.write(x & "<br />")
next'
检查并告诉我这是否可行 或者最初将所有数据保存在字符串中,然后将其拆分为数组
答案 5 :(得分:0)
不是答案或为什么“tricky”不好:
>> a = Array(1)
>> a = Split(Join(a, "||") & "||2", "||")
>> WScript.Echo a(0) + a(1)
>>
12
答案 6 :(得分:0)
基于Charles Clayton's answer,但略有简化...
' add item to array
Sub ArrayAdd(arr, val)
ReDim Preserve arr(UBound(arr) + 1)
arr(UBound(arr)) = val
End Sub
像这样使用
a = Array()
AddItem(a, 5)
AddItem(a, "foo")