Question

我尝试编写一个加密我的数据的代码，然后我尝试执行代码我得到一个错误：

import base64
import boto3
from Crypto.Cipher import AES

PAD = lambda s: s + (32 - len(s) % 32) * ' '


def get_arn(aws_data):
    return 'arn:aws:kms:{region}:{account_number}:key/{key_id}'.format(**aws_data)


def encrypt_data(aws_data, plaintext_message):
    kms_client = boto3.client(
        'kms',
        region_name=aws_data['region'])

    data_key = kms_client.generate_data_key(
        KeyId=aws_data['key_id'],
        KeySpec='AES_256')

    cipher_text_blob = data_key.get('CiphertextBlob')
    plaintext_key = data_key.get('Plaintext')

    # Note, does not use IV or specify mode... for demo purposes only.
    cypher = AES.new(plaintext_key, AES.MODE_EAX)
    encrypted_data = base64.b64encode(cypher.encrypt(PAD(plaintext_message)))

    # Need to preserve both of these data elements
    return encrypted_data, cipher_text_blob



def main():
    # Add your account number / region / KMS Key ID here.
    aws_data = {
        'region': 'eu-west-1',
        'account_number': '70117777xxxx',
        'key_id': 'xxxxxxx-83ac-4b5e-93d4-xxxxxxxx',
    }

    # And your super secret message to envelope encrypt...
    plaintext = b'Hello, World!'

    # Store encrypted_data & cipher_text_blob in your persistent storage. You will need them both later.
    encrypted_data, cipher_text_blob = encrypt_data(aws_data, plaintext)
    print(encrypted_data)


if __name__ == '__main__':
    main()

这是一个错误：

PAD = lambda s：s +（32 - len（s）％32）*'' TypeError：无法将str连接到字节也许谁知道哪里有问题？请建议

Answer 1

您的功能PAD旨在使用string输入，并使用bytes输入（示例中为b'Hello, World!'）进行调用。

PAD('Hello, World!')（没有领先b）有效。一种解决方案是将明文填充为string，然后将其转换为bytes，例如：

plaintext = PAD('Hello, world!') plaintext_bytes = plaintext.encode('utf-8')

有关如何将string转换为bytes，请参阅this StackOverflow question。

AWS加密TypeError：无法将str连接到字节

1 个答案: