创建API路径

Question

我用Flask创建了一个CRUD端点，但是当我尝试获取数据时，收到404错误。我尝试使用＆＃39; http://127.0.0.1:5002/albums/beck//＆＃39;来访问此终结点。和＆＃39; http://127.0.0.1:5002/albums/beck＆＃39;但仍然得到404.因为我提供了贝克＆＃39;作为艺术家的名字，我认为get方法运行良好。我想我添加的资源不正确。

class Artistdetails(Resource):
    def get(self, artist_name):
        conn = db_connect.connect()
        # Protect against SQL injection
        restricted_char = "!=<>*0&|/\\"
        for char in restricted_char:
            artist_name = artist_name.replace(char, "")
        query_db = conn.execute("SELECT DISTINCT album FROM album WHERE artist='{0}'".format(artist_name.title()))
        result = jsonify({'artistAlbumList': [i[0] for i in query_db.cursor.fetchall()]})
        return result

    def put(self, artist_name, album_name, album_name_new):
        conn = db_connect.connect()
        # Protect against SQL injection
        restricted_char = "!=<>*0&|/\\"
        for char in restricted_char:
            artist_name = artist_name.replace(char, "")
        query_db = conn.execute("UPDATE album SET album='{0}' WHERE artist='{1}' AND"
                                " album='{2}'".format(artist_name.title(), album_name.title(), album_name_new.title()))
        result = jsonify({'putAlbumId': [i[0] for i in query_db.cursor.fetchall()]})
        return result, 201

    def post(self, artist_name, album_name):
        conn = db_connect.connect()
        # Protect against SQL injection
        restricted_char = "!=<>*0&|/\\"
        for char in restricted_char:
            artist_name = artist_name.replace(char, "")
        query_db = conn.execute("INSERT INTO album (album, artist) VALUES"
                                " ({0},{1})".format(artist_name.title(), album_name.title()))
        result = jsonify({'postAlbumId': [i[0] for i in query_db.cursor.fetchall()]})
        return result, 201

    def delete(self, artist_name, album_name):
        conn = db_connect.connect()
        # Protect against SQL injection
        restricted_char = "!=<>*0&|/\\"
        for char in restricted_char:
            artist_id = artist_name.replace(char, "")
            album_id = album_name.replace(char, "")
        query_db = conn.execute("DELETE FROM album WHERE"
                                " artist_id='{0}' AND album_id='{1}'".format(artist_name, album_name)
                                )
        result = jsonify({'deleteAlbumId': [i[0] for i in query_db.cursor.fetchall()]})
        return result, 204

创建API路径

api.add_resource(Api, '/')
api.add_resource(Albums, '/albums')
api.add_resource(Artistdetails, '/albums/<string:artist_name>/<string:album_name>/<string:album_name_new>')
api.add_resource(Genreyear, '/albums/yr')
api.add_resource(Genrenum, '/albums/genre')
api.add_resource(Artists, '/artists')

Answer 1

这一行：

api.add_resource(Artistdetails,
    '/albums/<string:artist_name>/<string:album_name>/<string:album_name_new>')

它添加了Flask路由器的路径，使其期望/albums/<artist_name>/<album_name>/<album_name_new>，而您尝试请求/albums/<artist_name>，这与任何内容都不匹配。

快速解决问题的方法是：

api.add_resource(Artistdetails, '/albums/<string:artist_name>')

但是，您可能希望支持搜索界面的查询字符串参数，以便请求看起来更像这样：

/albums?artist=<string>&album_name=<string>

为此，documentation for Flask-RESTful reqparse会很有用。

在Flask中访问CRUD端点的问题

创建API路径

1 个答案: