Question

您好我花了20多个小时才弄清楚如何将图片从我的应用程序上传到服务器，我要上传的图片可以从相机或照片卷中拍摄.....这里是我的代码确实显示上传的进度，但没有到达服务器，从而得到负面的响应表格服务器..请帮助我..

  Alamofire.upload(multipartFormData: { multipartFormData in
            multipartFormData.append(UIImageJPEGRepresentation(image, 0.1)!, withName: imageName)
            for (key, value) in parameters {
                multipartFormData.append(value.data(using: String.Encoding.utf8)!, withName: key)
            }
        },
                         to: URL_USER_PROFILE_IMG_UPLOAD)
        { (result) in
            switch result {
            case .success(let upload, _, _):

                upload.uploadProgress(closure: { (progress) in
                    print("Upload Progress: \(progress.fractionCompleted)")
                })

                upload.responseJSON { response in
                    print(response.result.value)
                }

            case .failure(let encodingError):
                print(encodingError)
            }
        }

我的服务器代码在PHP中作为

    <?php

// Path to move uploaded files
$target_path = "profile-photos/";

// array for final json respone
$image_upload = array();
 $server_ip ="00.000.000.000";
//gethostbyname(gethostname());
// final file url that is being uploaded
$file_upload_url = 'http://' . $server_ip .'/'.'folder2017'.'    /'.'webser'.'/'. $target_path;



if(isset($_FILES['image']['name'])) {
$target_path=$target_path.$_FILES['image']['name'];
   if(move_uploaded_file($_FILES['image']['tmp_name'], $target_path))         {
        $image_upload=array('path'=>$file_upload_url,'response_code'=>1);
        echo json_encode($image_upload);
  }
  } else {

  $image_upload=array('response_code'=>0);
  echo json_encode($image_upload);
  }



?>

Answer 1

试试这个：

替换

multipartFormData.append(UIImageJPEGRepresentation(image, 0.1)!, withName: imageName)

使用

let imgData = UIImageJPEGRepresentation(image!, 1.0)!
multipartFormData.append(imgData, withName: "image", fileName: "image.jpg", mimeType: "image/jpg")

相机和画廊图片由alamofire在swift 3上传

1 个答案: