Question

我使用mongoose 4.11.10，我宣布了2个型号：User＆amp;任务。我的用户模型是：

let UserSchema = mongoose.Schema({
  name: {
    type: String,
    required: true,
    minlength: 1,
    maxlength: 15
  }
});
let User = mongoose.model("UserModel", UserSchema);

来自用户模型的片段：

let TaskSchema = mongoose.Schema({
  userName: {
    type: mongoose.Schema.ObjectId,
    ref: "User",
    required: false,
    minlength: [1, "Invalid name"],
    maxlength: [15, "Too big name"]
  }
});
let Task = mongoose.model("TaskModel", TaskSchema);

我有表格，我输入所有这些值：

<p>Add new task: </p>
<form action="/api/tasks/" method="post">
  Name:
  <input type="text" name="name">
  <br>
  Definition:
  <input type="text" name="definition">
  <br>
  Status:
  <input type="text" name="status">
  <br>
  Responsible user:
  <input type="text" name="userName">
  <br>
  Deadline:
  <input type="date" name="deadline" >
  <br><br>
  <input type="submit" value="SEND">
</form>

在服务器端我有控制器：

api.post("/tasks/", (req, res) => {
  let name = req.body.name;
  let definition = req.body.definition;
  let status = req.body.status;
  let userName = req.body.userName;
  let deadline = req.body.deadline;
  if (userName.length < 1) {
    Task.create({name: name}, {definition: definition}, {status: status}, {userName: "not delegated yet"}, {deadline: deadline})
      .then(() => {
        console.log("Insertion successful");
        res.redirect("/api/tasks");
      })
      .catch(err => {
        console.log("Cannot insert");
        throw err;
      })
  } else {
    Task.create({name: name}, {definition: definition}, {status: status}, {userName: userName}, {deadline: deadline})
      .then(() => Task.findOne({name: name}).populate("userName"))
      .then(() => {
        console.log("Insertion successful");
        res.redirect("/api/tasks");
      })
      .catch(err => {
        console.log("Cannot insert");
        throw err;
      })
  }
});

正如你所看到的，我想链接2个模式：我想在指定用户上“委托”任务，但现在populate（）mongoose方法不起作用:(我该如何解决这个问题？

我们将不胜感激任何帮助！

Answer 1

我发现了类似的问题，这可能对您有所帮助https://stackoverflow.com/questions/14730676/linking-2-mongoose-schemas

Answer 2

您将userName的类型定义为ObjectId，但name的类型是字符串。这是一种不匹配，人口无法发挥作用。

将类型更改为String。

let TaskSchema = mongoose.Schema({
    user: {
        type: String,
        ref: 'User',
        required: false,
        minlength: [1, "Invalid name"],
        maxlength: [15, "Too big name"]
    }
});

我建议您将userName重命名为user，以便在查询时添加更多清晰度

Task.findOne(...).populate('user').exec(function (err, task) {
    console.log(task.user.name);
});

如果您尝试在不向架构添加tasks数组的情况下获取特定用户的所有任务，则可以使用virtual population

UserSchema.virtual('tasks', {
    ref: 'Task', // The model to use
    localField: 'name', // Find task where `localField`
    foreignField: 'user' // is equal to `foreignField`
});

然后你可以做

User.findOne(...).populate('tasks').exec(function (err, user) {
    console.log(user.tasks);
});

在表单完成时使用填充

2 个答案: