下面的代码将每行的文本拆分为某个分隔符的新创建的行 通过改变拼接方法的第二个参数,可以给出起点。起始分隔符出现后的所有内容都将被拆分并放在新的行上
如何仅拆分出界处的第n个出现? (即第二个)
期望的结果应该是这样的:在第二个' /'开始分裂。定界符:
此:
的 PMC37516JG / DMM / 1946P / C.Q4.DUMMY
变为:
的 PMC37516JG / DMM
1946P / C.Q4.DUMMY
$('#tbl tr').each(function(){
var $this = $(this);
var arr = $this.text().split('/');
var firstTwo = arr.splice(0,2);
var firstEl = firstTwo.join('/').trim();
arr.unshift(firstEl);
var len = arr.length;
var i;
var $previous = $this;
for (i = 0; i < arr.length; ++i) {
var $tr = $this.clone();
$tr.find("td").text(arr[i]);
$previous.after( $tr );
$previous = $tr;
}
$this.remove();
});
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th {
height: 15px;
min-width: 30px;
border: 1px solid black;
font-size: 12px;
font-family: Courier, monospace;
padding: 2px 5px 2px 5px;
}
td {
height: 15px;
min-width: 30px;
border: 1px solid black;
font-size: 12px;
font-family: Courier, monospace;
padding: 2px 5px 2px 5px;
}
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<script src="https://ajax.googleapis.com/ajax/libs/jquery/2.1.1/jquery.min.js"></script>
<table id="tbl">
<thead>
<tr class="tbl-header">
<th>1</th>
</tr>
</thead>
<tbody>
<tr>
<td>UWS</td>
</tr>
<tr>
<td>DA8101A/12.DOH</td>
</tr>
<tr>
<td>-PMC37516JG/DMM/1946P/C.Q4.DUMMY</td>
</tr>
<tr>
<td>-PMC18713DA/DMM/2118P/C.Q4</td>
</tr>
<tr>
<td>-PMC17854DA/DMM/1884P/C.Q5.KIKKER</td>
</tr>
<tr>
<td>-PMC18964DA/DMM/1270P/C.Q5</td>
</tr>
<tr>
<td>-PMC13312DA/DMM/1500P/C.Q5</td>
</tr>
<tr>
<td>-PMC81630FF/DMM/2316P/C.Q5.DUMMY</td>
</tr>
<tr>
<td>-PMC73647FF/DMM/2540P/C.Q5.DUMMY</td>
</tr>
<tr>
<td>-PMC15970DA/DMM/2780P/C.Q5</td>
</tr>
<tr>
<td>-PMC19458DA/DMM/2644P/C.Q5</td>
</tr>
<tr>
<td>-PMC13485DA/DMM/2382P/C.Q5.KIKKER</td>
</tr>
<tr>
<td>-PMC88130FF/DMM/2450P/C.Q5</td>
</tr>
<tr>
<td>-PMC13913DA/DMM/2930P/C.Q5</td>
</tr>
<tr>
<td>-PMC19689DA/DMM/3298P/C.Q5</td>
</tr>
<tr>
<td>-PGA2002DA/ORD/2155P/C.Q5.TRANSIT</td>
</tr>
<tr>
<td>-PMC11453DA/DMM/3212P/C.Q5</td>
</tr>
<tr>
<td>-PMC17664DA/ORD/1800P/C.Q4.TRANSIT</td>
</tr>
<tr>
<td>-PMC90443FF/DMM/520P/C.Q5</td>
</tr>
<tr>
<td>-PMC16529DA/DMM/624P/C.Q5</td>
</tr>
<tr>
<td>-PMC72784FF/DMM/4218P/C.Q5.DUMMY</td>
</tr>
<tr>
<td>-PMC94058FF/DMM/3120P/C.Q5.DUMMY</td>
</tr>
<tr>
<td>-PMC91247FF/DMM/3466P/C.Q5.KIKKER</td>
</tr>
<tr>
<td>-PMC38632JG/DMM/3094P/C.Q5</td>
</tr>
<tr>
<td>-PMC19767DA/DMM/3778P/C.Q5</td>
</tr>
<tr>
<td>-PMC16397DA/ORD/1420P/C.Q4.TRANSIT</td>
</tr>
<tr>
<td>-PMC12044DA/DMM/2672P/C.Q4</td>
</tr>
<tr>
<td>-PMC37949JG/DMM/1672P/C.Q6</td>
</tr>
<tr>
<td>-PMC13278DA/ORD/928P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC11256DA/ORD/1595P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC18938DA/ORD/1458P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC12294DA/ORD/4140P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC14236DA/ORD/4136P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC13867DA/ORD/4126P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC7523DA/ORD/4152P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC18036DA/ORD/4122P/C.PLD.TRANSIT</td>
</tr>
<tr>
<td>-PMC10478DA/DMM/1548P/C.PWG</td>
</tr>
<tr>
<td>-PMC88389FF/DMM/1164P/C.PLD</td>
</tr>
</tbody>
</table>
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答案 0 :(得分:1)
将您的脚本更改为低于1,请验证这是否适合您。
$('#tbl tr').each(function(){
var tr = $(this).find('td').text().split('/');
if (tr.length > 2){
//you can change below code to split it by first '/'
var p =tr.splice(0,2);
$(this).replaceWith('<tr><td>' +p.join('/') +'</td></tr> <tr><td>'+tr.join('/') +'</td></tr>')
}
});