Question

以下适用于Flask-Classful（它是现已废弃的Flask-Classy的维护叉），但我想知道是否有一个＆＃34; native＆＃34; Flask-Classful中最后两条路线的逻辑版本，没有混合Flask路线和Flask-Classful内置特殊方法，如get()和post()？

从Flask-Classy在https://pythonhosted.org/Flask-Classy/的大量文档中我遗憾地看不到下面代码中最后两条路线的例子，例如。 GET /news/123/comments/和GET /news/123/comments/321。有一些例子可能类似于GET /news/comments/123，但是当您从路径URI中选择两个变量（将用于数据库查询）时则不会这样。

from flask_classful import FlaskView, route


class NewsView(FlaskView):
    def index(self):
        return "This is GET /news\n"

    def get(self, news_id):
        return "This is GET /news/{}\n".format(news_id)

    def post(self):
        return "This is POST /news\n"

    def put(self, news_id):
        return "This is PUT /news/{}\n".format(news_id)

    def patch(self, news_id):
        return "This is PATCH /news/{}\n".format(news_id)

    def delete(self, news_id):
        return "This is DELETE /news/{}\n".format(news_id)

    @route("/<int:news_id>/comments/<int:comment_id>", methods=["GET"])
    def news_comment(self, news_id, comment_id):
        return "This is GET /news/{}/comments/{}\n".format(news_id, comment_id)

    @route("/<int:news_id>/comments/", methods=["GET"])
    def news_comments(self, news_id):
        return "This is GET /news/{}/comments/\n".format(news_id)

路线已注册：

def register_views(app):
    api_path = "/api/1.0"

    from apps.news.views import NewsView
    NewsView.register(app, route_base="{}/news/".format(api_path))

虽然似乎有用。也许它只是分裂，但我认为这样的东西会在Flask-Classful中有内置的支持吗？

这是一些测试请求，它起作用：

$ curl -X GET https://localhost:443/api/1.0/news/ --insecure -L
This is GET /news
$ curl -X GET https://localhost:443/api/1.0/news/123 --insecure -L
This is GET /news/123
$ curl -X POST https://localhost:443/api/1.0/news/ --insecure -L
This is POST /news
$ curl -X PUT https://localhost:443/api/1.0/news/123 --insecure -L
This is PUT /news/123
$ curl -X PATCH https://localhost:443/api/1.0/news/123 --insecure -L
This is PATCH /news/123
$ curl -X DELETE https://localhost:443/api/1.0/news/123 --insecure -L
This is DELETE /news/123
$ curl -X GET https://localhost:443/api/1.0/news/1/comments/ --insecure -L
This is GET /news/1/comments/
$ curl -X GET https://localhost:443/api/1.0/news/1/comments/2 --insecure -L
This is GET /news/1/comments/2

Answer 1

默认情况下，使用某个名称

创建方法时

class NewsView(FlaskView):
    def comments(self, news_id, comment_id):
        pass

默认情况下，上面会将其注册为/comments/<news_id>/<comment_id>，因为您的基本路线为news/。评论方法的最终路线将变为news/comments/<news_id>/<comment_id>。

然后是谁阻止我们改变它？

from flask import Flask, request, jsonify
import json

from flask_classy import FlaskView

app = Flask(__name__)


class MyFlaskView(FlaskView):
    @classmethod
    def build_rule(cls, rule, method=None):
        path = super(MyFlaskView, cls).build_rule(rule, method)
        parts = path.split("/")
        if len(parts) >= 3 and parts[-1].startswith("<") and parts[-2].startswith("<"):
            parts[-3], parts[-2] = parts[-2], parts[-3]
            return "/".join(parts)
        return path

class NewsView(MyFlaskView):

    def comments(self, news_id, comment_id):
        return "This is GET /news\n"

    def get(self, news_id):
        return "This is GET /news2\n"

if __name__ == "__main__":
   NewsView.register(app, route_base="news/")
   app.run(debug=True)

此重写方法会将您的路线注册为/news/<news_id>/comments/<comment_id>

Flask-Classy / Flask-Classful中的子路线

1 个答案: