我在2个字符串变量中有属性名称和值。当属性类型为例如string:
时,很容易设置prop.SetValue(P, Value, null);
但枚举类型怎么样? 看看这个例子:
public enum enmSex { Male, Female, Trans };
public enum enmMaritalStatus { Married, Single, Divorced, Widowed };
private class Person
{
public string GivenName { get; set; }
public int Age { get; set; }
public double Weight { get; set; }
public enmSex Sex { get; set; }
public enmMaritalStatus MaritalStatus { get; set; }
}
private List<Person> People = new List<Person>();
private void SetPersonProperty(string GivenName, string Property, string Value)
{
Person P = People.Where(c => c.GivenName == GivenName).First();
PropertyInfo prop = typeof(Person).GetProperties().Where(p => p.Name == Property).First();
if (prop.PropertyType == typeof(double))
{
double d;
if (double.TryParse(Value, out d))
prop.SetValue(P, Math.Round(d, 3), null);
else
MessageBox.Show("\"" + Value + "\" is not a valid floating point number.");
}
else if (prop.PropertyType == typeof(int))
{
int i;
if (int.TryParse(Value, out i))
prop.SetValue(P, i, null);
else
MessageBox.Show("\"" + Value + "\" is not a valid 32bit integer number.");
}
else if (prop.PropertyType == typeof(string))
{
prop.SetValue(P, Value, null);
}
else if (prop.PropertyType.IsEnum)
{
prop.SetValue(P, Value, null); // Error!
}
}
private void button1_Click(object sender, EventArgs e)
{
People.Add(new Person { GivenName = "Daniel" });
People.Add(new Person { GivenName = "Eliza" });
People.Add(new Person { GivenName = "Angel" });
People.Add(new Person { GivenName = "Ingrid" });
SetPersonProperty("Daniel", "Age", "18");
SetPersonProperty("Eliza", "Weight", "61.54442");
SetPersonProperty("Angel", "Sex", "Female");
SetPersonProperty("Ingrid", "MaritalStatus", "Divorced");
SetPersonProperty("Angel", "GivenName", "Angelina");
}
private void button2_Click(object sender, EventArgs e)
{
foreach (Person item in People)
MessageBox.Show(item.GivenName + ", " + item.Age + ", " +
item.Weight + ", " + item.Sex + ", " + item.MaritalStatus);
}
答案 0 :(得分:0)
您需要将Value
中的字符串解析为所需的枚举类型:
var enumValue = Enum.Parse(prop.PropertyType, Value);
然后将其传递给SetValue()
:
prop.SetValue(P, enumValue, null);