Question

从％m-％d-％Y格式的给定日期起，我们应该确定它是哪一天请帮我完成命令

如果我通过了像09-01-2017那样的日期输出应该是星期五

Answer 1

很简单。只需使用日期命令本身和正确的选项。

$ date -j -f '%m-%d-%Y' "09-01-2017" +'%A'
Friday

Answer 2

monday-sunday

这将产生一周中的某一天MM-DD-YYYY 如果输入日期严格采用IFS='-' read -ra ADDR <<< "09-01-2017" formattedDate=${ADDR[2]}-${ADDR[0]}-${ADDR[1]} date -d $formattedDate +%A格式，请使用以下

{{1}}

第一行标记日期的组成部分，第二行重新排列它们

Answer 3

如果您的日期如下：

d="09-01-2017"

您需要将其重新格式化为＆＃34; YYYY-MM-DD＆＃34;

date -d $(echo $d|awk -F- '{print $3 "-" $1 "-" $2}') +%A # DOW

Answer 4

这是我通常要做的。我会使用日期功能。您可以进行“约会”并找到选项。

$ d=2020-08-20 \
$ date -d "$d" +%u \
4 \
$ date -d "$d" +%A \
Thursday

Answer 5

您可以将其作为％m /％d％Y传递，并由date命令识别。

$ date --date="`echo 09-01-2017| sed -e 's/-/\//g' `" +'%A'
Friday

要进行验证，请通过％F以获得ISO格式

$ date --date="`echo 09-01-2017| sed -e 's/-/\//g' `" +'%A %F'
Friday 2017-09-01

Answer 6

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我们如何根据unix中的给定日期获得工作日

6 个答案: