从数组

Question

所以我有一个数组，其中包含几个完全相同的编号条目，如下所示：

var levels = new Object;
levels = {
    0:{
        name: "xxx1",
        ratesBR: {
            stone: 1,
            wood: 5,
            copper: 0,
        }
        ratesFS: {
            food: 10,
            water: 10,
            sacrifice: 0,
        }
    }
    1:{
        name:"xxx2",
        ratesBR: {
            stone: 1,
            wood: 5,
            copper: 0,
        }
        ratesFS: {
            food: 10,
            water: 10,
            sacrifice: 0,
        }
    }
}

所以我的问题就是这样，说我想在所有“等级”（0,1等）中使用

检查'石头'是否大于或等于1

if levels.XX.ratesBR.wood >= 1

但是代替XX，我想知道我可以用来表示我所看过的“全部”，而我最接近的是every（）函数，但我认为这不是我想要的。我不知道“全部”能指甚至会被称为什么，所以我转向你们的方向进去。谢谢。

Answer 1

  

所以我有一个阵列......

这不是一个数组，它是一个非数组对象。它只有属性名"0"，"1"等等（是的，它们是字符串，即使它们已被写成数字）。

  

我最接近的是every（）函数，但我认为这不是我要找的。

确实如此，但将它应用于非数组对象有点尴尬。我们可以使用Object.keys获取对象的密钥，然后在其上使用every。

在ES5中，你可以这样做：

if (Object.keys(levels).every(function(key) { return levels[key].ratesBR.wood >= 1; })) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

直播示例：

var levels = {
  0: {
    name: "xxx1",
    //lifeStage: 
    ratesBR: {
      stone: 1,
      wood: 5,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  },
  1: {
    name: "xxx2",
    //lifeStage:
    ratesBR: {
      stone: 2,
      wood: 0,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  }
};

if (Object.keys(levels).every(function(key) { return levels[key].ratesBR.wood >= 1; })) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

在ES2015 +中，箭头功能可以使其更简洁：

if (Object.keys(levels).every(key => levels[key].ratesBR.wood >= 1)) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

直播示例：

var levels = {
  0: {
    name: "xxx1",
    //lifeStage: 
    ratesBR: {
      stone: 1,
      wood: 5,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  },
  1: {
    name: "xxx2",
    //lifeStage:
    ratesBR: {
      stone: 2,
      wood: 0,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  }
};

if (Object.keys(levels).every(key => levels[key].ratesBR.wood >= 1)) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

如果levels确实是一个数组（我建议使用），您只需直接使用every：

// IF `levels` WERE AN ARRAY
if (levels.every(entry => entry.ratesBR.wood >= 1)) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

直播示例：

var levels = [
  {
    name: "xxx1",
    //lifeStage: 
    ratesBR: {
      stone: 1,
      wood: 5,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  },
  {
    name: "xxx2",
    //lifeStage:
    ratesBR: {
      stone: 2,
      wood: 0,
      copper: 0
    },
    ratesFS: {
      food: 10,
      water: 10,
      sacrifice: 0
    }
  }
];

if (levels.every(entry => entry.ratesBR.wood >= 1)) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

ES5版本：

// IF `levels` WERE AN ARRAY
if (levels.every(function(entry) { return entry.ratesBR.wood >= 1; })) {
    console.log("All are >= 1");
} else {
    // No, at least one isn't
    console.log("At least one isn't >= 1");
}

Answer 2

你可以这样做：

var levels = {
  0:{
    name: "xxx1",
    //lifeStage: 
    ratesBR: {
      stone: 1,
      wood: 5,
      copper: 0
    },
    ratesFS: {
    food: 10,
    water: 10,
    sacrifice: 0
  }
},
1:{
    name: "xxx1",
    //lifeStage: 
    ratesBR: {
      stone: 1,
      wood: 5,
      copper: 0
    },
    ratesFS: {
    food: 10,
    water: 10,
    sacrifice: 0
  }
}
}

var array = $.map(levels, function(value, index) {
    return [value];
});
for(var i =0; i < array.length; i++){
  console.log(array[i].ratesBR.stone);
}