Question

我希望将我的用户表列名（profile_img）中的值插入到我的新闻表中，以及用户提交的其他信息列名（profile_img1）。

以下是我目前使用的查询

$name=$_REQUEST["title"];
$stdate=$_REQUEST["sdate"];
$endate=$_REQUEST["edate"];
$staddr=$_REQUEST["staddr"];
$addr2=$_REQUEST["staddr2"];
$city=$_REQUEST["city"];
$state=$_REQUEST["state"];
$zip=$_REQUEST["zip"];
$desc=$_REQUEST["desc"];
$file=$_REQUEST['photo'];
$link=$_REQUEST["link"];
$user=$_REQUEST["user"];
$profile_img1=$_REQUEST["profile_img1"];
$rsvp=$_REQUEST["rsvp"];        

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) VALUES('" . mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) . "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','".str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) ."-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) . "','$user','" . mysql_real_escape_string($rsvp)."')";

profile_img1的名称将在查询中的用户值之后，但我无法弄清楚如何将users表中的profile_img的名称获取到新闻表

这是我一直在尝试的：

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) VALUES('" . mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) . "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','".str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) ."-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) . "','$user','(SELECT profile_img FROM users WHERE username=`username`)''" . mysql_real_escape_string($rsvp)."')";

使用此方法会导致新闻表中的profile_img1列读取（SELECT profile_img FROM users WHERE username = username），而不是profile_img列在users表中读取的内容。

此外，如果我添加第二个INSERT查询

$q2 = mysql_query("INSERT INTO news (profile_img1) SELECT profile_img FROM users WHERE username='username'");

该查询导致在新闻表中创建一个新行，仅显示users表中的profile_img，与用户将输入的其他数据分开。

我想要的结果是让用户将数据提交到新闻表，并且用户表中的用户图像将被插入到行中的新闻表中，其他数据被提交，因此提交的数据和用户图像是一起显示。

如果您需要更多说明，请告诉我

Answer 1

您是否已拥有profile_img1的值？

$profile_img1=$_REQUEST["profile_img1"];

但无论如何，当然如果你做2次插入，它会插入2行。

你想查找更新。

和mysql_insert_id（）一起获取最后一次插入的id。

在（最后，在你知道你在做什么之后）：

UPDATE news SET profile_img1 = "whateveritis" where id = theidoftherowyoujustinserted

Answer 2

简短的回答是做INSERT（...）SELECT ...

e.g。

$name=$_REQUEST["title"];
$stdate=$_REQUEST["sdate"];
$endate=$_REQUEST["edate"];
$staddr=$_REQUEST["staddr"];
$addr2=$_REQUEST["staddr2"];
$city=$_REQUEST["city"];
$state=$_REQUEST["state"];
$zip=$_REQUEST["zip"];
$desc=$_REQUEST["desc"];
$file=$_REQUEST['photo'];
$link=$_REQUEST["link"];
$user=$_REQUEST["user"];
$profile_img1=$_REQUEST["profile_img1"];
$rsvp=$_REQUEST["rsvp"];        

$query = "INSERT INTO news (fname,stdate,endate,addr1,addr2,city,state,zip,name,size,type,content,link,description,user,profile_img1,rsvp) SELECT '" . 
    mysql_real_escape_string($name) . "','$stdate','$endate','" . mysql_real_escape_string($staddr) .
    "','" . mysql_real_escape_string($addr2) . "','" . mysql_real_escape_string($city) . "','$state','$zip','".
    str_replace([",",":","\"","\\", "/", "*"," ","$","&","?",";","'","!","(",")","|","~","<",">","=","[","]","{","}","#","^","%","=","@","+","è","é"],"",$name) .
    "-".$stdate."-".$file."','0',' ',' ','" . mysql_real_escape_string($link)."','" . mysql_real_escape_string($desc) .
    "',provile_img,'" . 
    mysql_real_escape_string($rsvp)."'" .
    " FROM users WHERE username = '{$username}'";

这应该变成：

INSERT INTO news (fname, stdate, profile_img1, rsvp)
SELECT 'Bob', '2017-09-02', profile_img, 0
FROM users
WHERE username = 'jimbob'

长篇答案涉及请求不要自己进行转义并重新构造这一点以使其更易于阅读，并且通过扩展，以后更容易维护

如何使用另一个表中的名称插入值

2 个答案: