在Hive中查找员工的最后两位数员工ID

Question

我在Hive中有以下场景

Emp ID | Employee name | Emp salary    
112    | Prakash       | 33333       
212    | Aakash        | 5567
322    | Kishore       | 565
3242   | hhjh          | 76676
4325   | chhh          | 565
422    | Ramesh        | 34555

我想找出员工ID最后两位数相同的员工姓名：

例如。 Prakash和Aakash拥有员工ID相同的最后一位数字。 Kishore和Ramesh也有相同的。

输出：

112    | Prakash            
212    | Aakash       
322    | Kishore  
422    | Ramesh  

Answer 1

select  `Emp ID`
       ,`Employee name`

from   (select  `Emp ID`
               ,`Employee name`
               ,count(*) over (partition by `Emp ID` % 100) as cnt

        from    mytable
        ) t

where   cnt > 1
;

+--------+---------------+
| emp id | employee name |
+--------+---------------+
|    212 | Aakash        |
|    112 | Prakash       |
|    422 | Ramesh        |
|    322 | Kishore       |
+--------+---------------+