通过使用触发器比较两个表的值来更新第三个表

时间:2011-01-05 06:20:19

标签: mysql triggers

斐伊川

我有三个表(Table1,Table2,Table3)。这三个表都有相同的列名(Company,License_count)。当table2中发生更新时,触发器将比较table2&的值。 table1并将差异插入表三。我必须只为单行做这件事。

有人可以帮忙吗?

1 个答案:

答案 0 :(得分:0)

好吧,我明白了。

drop trigger if exists table1and2difference;
CREATE TRIGGER table1and2difference
AFTER UPDATE ON Table2
FOR EACH ROW
  INSERT INTO Table3(Company, License_count)values
    (new.Company, (SELECT (SUM(License_count1) - License_count2) as License_count FROM
                   (SELECT Company as company1, License_count as License_count1 FROM 
                           Table1 WHERE Company=new.Company) AS t1
                   INNER JOIN
                   (SELECT Company as company2, License_count as License_count2 FROM
                           Table2 WHERE Company=new.Company) As t2
                   On company1=company2));

作为参考,这些是我用来测试触发器的值。

create table Table1(
Company VARCHAR(100) NOT NULL,
License_count INT NOT NULL);

insert into Table1(Company,License_count)values('Test_company',10);

create table Table2(
Company VARCHAR(100) NOT NULL,
License_count INT NOT NULL);

insert into Table2(Company,License_count)values('Test_company',8);

create table Table3(
Company VARCHAR(100) NOT NULL,
License_count INT NOT NULL);

drop trigger if exists table1and2difference;
CREATE TRIGGER table1and2difference
AFTER UPDATE ON Table2
FOR EACH ROW
     INSERT INTO Table3(Company, License_count)values
         (new.Company, (SELECT (SUM(License_count1) - License_count2) as License_count FROM
                            (SELECT Company as company1, License_count as License_count1 FROM Table1 WHERE Company=new.Company) AS t1
                            INNER JOIN
                            (SELECT Company as company2, License_count as License_count2 FROM Table2 WHERE Company=new.Company) As t2
                            On company1=company2));

update Table2 set License_count=7;