R：带有mtext的直方图字幕：如何在列中获得表格对齐？

Question

我有一个多行字幕的情节：

文字的当前代码：

bq1 <- bquote("Raw: "
              ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday$steps), digits=2), big.mark=","))
              ~ ", " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday$steps), digits=2), big.mark = ","))
              ~ ", median ="
              ~ .(format(median(stepsperday$steps), big.mark = ","))
)

bq2 <- bquote("Imputed: "
              ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday.imputed$steps), digits=2), big.mark=","))
              ~ ", " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday.imputed$steps), digits=2), big.mark = ",", digits = 6))
              ~ ", median ="
              ~ .(format(median(stepsperday.imputed$steps), big.mark = ","))
)

mytext <- list(bq2, bq1)
mtext(do.call(expression, mytext),side=3,line=0:1, cex=.75)

我希望2条线在各自的数据位上水平对齐 - 平均值，sd，中位数，就像它们在表格中一样。

有没有办法做到这一点？

感谢任何提示，

SFF

Answer 1

根据评论，以下内容足够：

data1 <- "      Raw:"
data2 <- "Imputed:"
mytext1 <- list(data2, data1)
mtext(do.call(expression, mytext1), side=3, line=0:1, adj=c(.23, .23), cex=.75)

bq1 <- bquote("  " ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday$steps), digits=2), big.mark=","))
              ~ " " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday$steps), digits=2), big.mark = ","))
              ~ " median ="
              ~ .(format(median(stepsperday$steps), big.mark = ","))
)

bq2 <- bquote("   " ~ mu 
              ~ "=" 
              ~ .(format(round(mean(stepsperday.imputed$steps), digits=2), big.mark=","))
              ~ " " 
              ~ sigma 
              ~ "=" 
              ~ .(format(round(sd(stepsperday.imputed$steps), digits=2), big.mark = ",", digits = 6))
              ~ "   median ="
              ~ .(format(median(stepsperday.imputed$steps), big.mark = ","))
)

mytext <- list(bq2, bq1)
mtext(do.call(expression, mytext), side=3, line=0:1, adj=c(.6, .6), cex=.75)

产生输出：