复杂的SQL查询在同一个表中查找数字差异

Question

有人可以帮我写一个SQL服务器查询，它会从当前数据中得到预期结果。我需要在每个位置之间找到米差距。

Answer 1

只需使用sfl.getCompleteValue().getSharedFolderId();并将其与LEAD（读取表数据一次）结合使用，就像这样

subquery

但是我按select tt.PersonId, tt.PreviousPosition, tt.NextPosition, tt.NextMeter - tt.previousMeter from (select PersonId, t.position PreviousPosition, LEAD(Position) OVER(order by Position) NextPosition, t.Meter PreviousMeter, LEAD(Meter) OVER(order by Position) NextMeter from myTable t) tt where tt.NextPosition is not null 排序，如果你有一些键（继续插入排序）或者你有一些特殊的逻辑与惰性和排序只使用排序中的列

Answer 2

尝试这样的事情。

SELECT id, position as previous,(
       SELECT TOP 1 position
       FROM table t1
       WHERE ti.position > t2.position
       ORDER BY
             position
       ) as next, 
       (
       SELECT TOP 1 meter
       FROM table t1
       WHERE ti.position > t2.position
       ORDER BY
             position
       ) - meter AS gap
FROM table t2
ORDER BY position

Answer 3

试试这个（我必须为您的数据添加一个独特的PK列）

CREATE TABLE #Data
(
    ID INT,
    PersonId INT,
    Position INT,
    Meter INT
)

INSERT INTO #Data VALUES (1,1,10,10),(2,1,22,20),(3,1,34,35),(4,1,46,46)

SELECT  PersonId,
        Position AS PreviousPosition,
        LEAD(Position) OVER (ORDER BY ID) NextPosition,
        Meter as ThisMeter,
        LEAD(Meter) OVER (ORDER BY ID) NextMeter
INTO    #Results
FROM    #Data

SELECT PersonId,
       PreviousPosition,
       NextPosition,
       NextMeter - ThisMeter AS MetreGap
FROM   #Results
WHERE  NextPosition IS NOT  NULL

DROP TABLE #Results
DROP TABLE #Data

Answer 4

您可以尝试以下查询以获取所需的输出

    select t1.persionid,t1.position prev_position,t2.position next_position,t2.meter-t1.meter meter_gap from
  (select personid,position,meter,row_number() over( order by position,meter) rn1 from table) as t1 join (select personid,position,meter,row_number() over( order by position,meter) rn2 from table) as t2 on (t1.rn1+1=t2.rn2)