我正在尝试获取单个用户的详细信息,包括他通过网站所做的所有评论(来自评论模式),但是每当我运行查询时,我都会获得 TypeError :(中间值) ).populate不是函数。我在互联网上以及在stackoverflow上搜索了相同的错误消息,但没有运气
显示路线
// profile page search
app.get("/:username", function(req, res) {
User.findOne({ username: username }.populate("comments").exec(function(err, user) {
if (err) {
console.log(err);
res.redirect("error");
} else {
if (user === null)
res.render("invalid");
else
res.render("profile", { user: user });
}
}));
});
userSchema
var mongoose = require("mongoose");
var passportLocalMongoose = require("passport-local-mongoose");
var UserSchema = new mongoose.Schema({
id: String,
fullname: String,
username: String,
comments: [
{
type: mongoose.Schema.Types.ObjectId,
ref: "Comment"
}
]
});
UserSchema.plugin(passportLocalMongoose);
module.exports = mongoose.model("User", UserSchema);
评论架构
var mongoose = require("mongoose");
var commentSchema= mongoose.Schema({
text: String,
author: {
id: {
type: mongoose.Schema.Types.ObjectId,
ref: "User"
},
username: String
}
});
module.exports = mongoose.model("comments", commentSchema);
我完全迷失在这里,请帮忙 提前致谢
答案 0 :(得分:1)
您的右括号)
的位置是错误的。只需在populate
之前移动括号,它就应该有效。像这样:
// profile page search
app.get("/:username", function(req, res) {
User.findOne({ username: username }).populate("comments").exec(function(err, user) {
if (err) {
console.log(err);
res.redirect("error");
} else {
if (user === null)
res.render("invalid");
else
res.render("profile", { user: user });
}
});
});
答案 1 :(得分:1)
// profile page search
app.get("/:username", function(req, res) {
User.findOne({ username: username })
.populate("comments")
.exec(function(err, user) {
if (err) {
console.log(err);
res.redirect("error");
} else {
if (user === null)
res.render("invalid");
else
res.render("profile", { user: user });
}
});
});