Question

我正在使用角度4，我尝试从2个端点获取数据，但我在理解rxjs时遇到了问题。

使用此代码我只能获得学生和用户的列表。

 getStudent() {
    return this.http.get(this.url + this.student_url, this.getHeaders()).map(res => res.json());
  }

getUsers() {
    return this.http.get(this.url + this.users_url, this.getHeaders()).map(res => res.json());
  }

我们说这是数据：学生

[{"ID" : 1 , "SchoolCode": "A150", "UserID": 1 }, 
{"ID" : 5 , "SchoolCode": "A140" , "UserID": 3}, 
{"ID" : 9 , "SchoolCode": "C140" , "UserID": 4}]

用户

[{"ID" : 1  ,"Name": "Rick" , "FamilyName" , "Grimes" },
{"ID" : 4 ,"Name": "Carle" , "FamilyName" , "Grimes" }]

我想先得到所有学生，然后比较UserID，如果它与用户相同，那么我将两个对象合并为一个，直到得到这样的数组：

{"ID" : 1 , "SchoolCode": "A150","Name": "Rick" , "FamilyName" , "Grimes" }

我认为我应该使用flatmap但是我确实尝试过编写代码，但它对我不起作用，我没有找到这样的逻辑示例。

你能帮帮我吗。

Answer 1

您可以在以下代码中使用switchMap运算符（别名flatMap）：

// Observables mocking the data returned by http.get()
const studentObs = Rx.Observable.from([
  {"ID" : 1 , "SchoolCode": "A150", "UserID": 1 }, 
  {"ID" : 5 , "SchoolCode": "A140" , "UserID": 4}, 
  {"ID" : 9 , "SchoolCode": "C140" , "UserID": 3}
]);
const userObs = Rx.Observable.from([
  {"ID" : 1, "Name": "Rick" , "FamilyName": "Grimes" },
  {"ID" : 3, "Name": "Tom" , "FamilyName": "Cruise" },
  {"ID" : 4, "Name": "Amy" , "FamilyName": "Poehler" }
]);
// Return an observable emitting only the given user.
function getUser(userID) {
  return userObs.filter(user => user.ID === userID);
}

studentObs
  .switchMap(student => {
     return getUser(student.UserID).map(user => {
       // Merge the student and the user.
       return Object.assign(student, {user: user});
     })
  })
  .subscribe(val => console.log(val));

查看此JSBin：http://jsbin.com/batuzaq/edit?js,console

Answer 2

您可以尝试以下方法：

import { forkJoin } from 'rxjs/observable/forkJoin';

interface Student {
  id: number;
  schoolCode: string;
  userId: number;
}

interface User {
  id: number;
  name: string;
  familyName: string;
}

interface Merged {
  id: number;
  schoolCode: string;
  name: string;
  familyName: string;
}

getStudents(): Observable<Student[]> {
    // Implementation
  }

  getUsers(): Observable<User[]> {
    // Implementation
  }

  getMerged(): Observable<Merged[]> {
    const student$ = this.getStudents();
    const users$ = this.getUsers();
    const merged$ = forkJoin(student$, users$)
      .map(src => src[0].reduce((acc, current) => {
        // acc is the accumulated result (list with mapped objects)
        // current is an element of the students list
        const user = src[1].find(u => u.id === current.userId);
        // check if there is a user associated to the current student element
        if (user) { // if there is a matching user, push new element to result list
          acc.push({
            id: user.id,
            name: user.name,
            familyName: user.familyName,
            schoolCode: current.schoolCode
          });
        }
        return acc;
        // this could be changed to use a more immutable based approach
      }, new Array<Merged>()));
      // the seed value to start accumulating results is an empty list
    return merged$;
  }

Angular 4组合来自多个HTTP请求的数据

2 个答案: