我理解这个问题可能会被问到,但我尝试使用我在这里找到的解决方案,但他们并没有为我工作。如果电子邮件列存在,我需要更新数据库中的数据,否则应该插入新记录。 以下是我的代码。
<?php
$dbhost = 'localhost';
$dbuser = 'root';
$dbpass = '';
$db = 'mbf';
$dbconn = mysql_connect($dbhost, $dbuser, $dbpass);
mysql_select_db($db);
$dat = date("Y-m-d H:i:s");
$date = new DateTime();
$date->modify('+4 weeks');
if(isset($_POST['submit'])) {
$email = $_POST['email'];
$dat = $_POST['date'];
$ghdate = $_POST['ghdate'];
$amount = $_POST['amount'];
$iniamount = $_POST['iniamount'];
$outamount = $_POST['outamount'];
$ghamount = $_POST['ghamount'];
$query = "INSERT INTO donation (email, date, ghdate, amount,
inamount, outamount, ghamount) VALUES ('$email', '$dat',
'$ghdate','$amount',
'$iniamount', '$outamount', '$ghamount')
ON DUPLICATE KEY UPDATE
email='$email', date='$dat', amount='$amount', inamount='$iniamount',
outamount='$outamount', ghamount='$ghamount'";
if(mysql_query($query))
{
echo "<script>alert('Donation of $amount was successful');</script>";
}
else
{
echo "<script>alert('FAILED TO INSERT');</script>";
}
}
?>
它不会更新电子邮件列,而是会插入新记录。
答案 0 :(得分:2)
ON DUPLICATE KEY UPDATE
语句才有效。确保电子邮件字段在表模式中具有UNIQUE约束。