Question

当我点击button1时，button2将变为红色，当我第二次点击button1时，button2将变为黄色。当button2为蓝色时，单击button1后，button2将变回红色。我的代码不正确，但我希望编写与此类似的代码。

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         

    String[] colorsArray = {"red","yellow","green","blue"};

    for(int i = 0; i < 4; i++)
        jButton2.setBackground(Color.colorsArray[i]);
}

代码错误：

无法找到符号

symbol：variable colorsArray

location：class Color

Answer 1

试试这个

 private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         

        String[] colorsArray = {"red","yellow","green","blue"};

        for(int i = 0; i <= 4; i++)
            jButton2.setBackground(Color.colorsArray[i]);
        }

Answer 2

编辑：您的颜色数组与此方法属于同一个类，而不是名为Color的类，如Color.colorsArray代码所示。代码已修复

您不需要for循环。您需要存储BT2的当前状态，并在到达结束时循环。

这样你就可以从currentColor == 0开始。单击按钮时，设置红色BG，设置currentColor == 1。下次，将其设置为黄色。当currentColor == 4将其设置为0以重新开始时。

// put this outside method, as class member
private final String[] colorsArray = {"red","yellow","green","blue"};
private int currentColor = 0;

private void jButton1ActionPerformed(java.awt.event.ActionEvent evt) {                                         
    if (currentColor == colorsArray.length) {
        currentColor = 0;
    }

    jButton2.setBackground(colorsArray[currentColor]);

    currentColor = currentColor + 1;
}

单击Button1，Button2将根据Java中的顺序更改为多种颜色

2 个答案: