Question

我想从一个表和用户选择中获取多个行数据，只将选定的行存储到另一个表中。

此代码的问题是表'FLIGHTS'中的数据是从数据库中准确获取的，但是当我尝试将其存储到另一个表'bookFlight'时，它只存储所有列的NULL值。想要帮助！

<?php

$username = "root"; 
$password = ""; 
$hostname = "localhost"; 
$dbhandle = mysql_connect($hostname, $username, $password)  
            or die("Unable to connect to MySQL");
$selected = mysql_select_db("dbtest",$dbhandle)
            or die("Could not select dbtest");

session_start();

         ////// STORING DATA INTO TABLE 'bookFlight' ////////

 if(isset($_POST['Submit']))
{
         $company_name   = mysql_real_escape_string($_POST['company_name']);
         $flight_category= mysql_real_escape_string($_POST['flight_category']);
         $rates           = mysql_real_escape_string($_POST['rates']);
         $qry    = "INSERT INTO bookFlight"."(company_name,flight_category,rates)". 
                  "VALUES('$company_name','$flight_category','$rates')"; 

    $retval = mysql_query( $qry, $dbhandle );
    if(! $retval ) {
           die('<br><br> Could not enter data: ' . mysql_error());
        }
      else  {  echo "Entered data successfully\n";   }               
}
              ////// FETCHING DATA FROM TABLE 'flights' ////////

$sql = "SELECT * FROM flights where type_id = 
                                      (SELECT type_id FROM tour WHERE city = 
                                     '{$_SESSION['destination_Address']}')";

$myData = mysql_query($sql,$dbhandle);
$num = mysql_num_rows($myData);

  echo "<table border=1>
  <tr>
  <th> COMPANY NAME :  </th>
  <th> FLIGHT CATEGORY : </th>
  <th> RATES :  </th>
  </tr>";

 for ($i=0; $i <$num; $i++)
{
$record = mysql_fetch_array($myData,MYSQL_ASSOC); 
echo "<form method=post>";
  echo "<tr>";
  echo "<td>" . $company_name[]= $record['company_name']      ."</td>";
  echo "<td>" . $flight_category[]= $record['flight_category']."</td>";
  echo "<td>" . $rates[]= $record['rates']                    ." </td>";
  echo "<td>" . "<input type='submit' name='Submit' value='SELECT'></td>";
  echo "</tr>";  
}
echo"</table>";
echo "</form>";

?>

Answer 1

那是因为你没有向你的表单发送除submit之外的任何内容，这就是为什么$_POST数组除了submit值之外什么都没有。

您需要传递行ID （我假设在这种情况下是 id 列）以及表单数据，以便您可以插入 < / em> bookFlight表中的特定行。

for ($i=0; $i <$num; $i++){ $record = mysql_fetch_array($myData,MYSQL_ASSOC); echo "<form action='?id=".$record['id']."' method='post'>"; ... }

一旦用户点击提交按钮，您就可以INSERT数据。

if(isset($_POST['Submit'])){ $qry = "INSERT INTO bookFlight (company_name, flight_category, rates) SELECT company_name, flight_category, rates FROM flights WHERE id = '".$_GET['id']."'"; $retval = mysql_query( $qry, $dbhandle ); if(! $retval ) { die('<br><br> Could not enter data: ' . mysql_error()); }else { echo "Entered data successfully\n"; } }

旁注：不使用mysql_*函数，从PHP 5.5开始不推荐使用它们，在PHP 7.0中完全删除它们。请改用mysqli或pdo。 And this is why you shouldn't use mysql_* functions。

从一个表中获取多行并将其存储到php Mysql中的另一个表

1 个答案: