如何迭代值为列表的哈希映射的结果?

时间:2017-08-31 15:10:30

标签: java hashmap

我创建了一个哈希映射,它将组合了三个参数的唯一键分组,即customer,sc和admin。我想创建一个唯一的密钥列表,其中包含附加的服务器列表。我已经实现了以下内容:

public static void main(String[] args) {

        String items = "customer1^sc1^admin1|server1~" +
                "customer1^sc1^admin1|server2~" +
                "customer1^sc1^admin1|server3~" +
                "customer2^sc1^admin1|server1~" +
                "customer3^sc1^admin1|server3~" +
                "customer3^sc1^admin1|server2~";

        // Set up raw data
        List<String> splitItems = Arrays.asList(items.split("\\s*~\\s*"));

        // Display raw data
        System.out.println("Raw List: " + items);

        // Create a hash map containing customer name as key and list of logs as value
        HashMap<String, List<String>> customerHashMap = new HashMap<>();

        // Loop through raw data
        for (String item : splitItems) {

            // Create new lists. One for customers and one for logs
            // List<String> customerList = new ArrayList<>();
            List<String> logList;

            String list[] = item.split("\\|");

            String customer = list[0];
            String log = list[1];

            logList = customerHashMap.get(customer);
            if (logList == null){
                logList = new ArrayList<>();
                customerHashMap.put(customer, logList);
            }

            logList.add(log);
            // System.out.println(logList);
        }

        // Print out of the final hash map. Customer "a" should only have "a" logs, customer "b" with "b", etc.
        System.out.println("");
        List<String> hashMapList = new ArrayList<String>();
        Iterator it = customerHashMap.entrySet().iterator();
        while (it.hasNext()) {
            Map.Entry pair = (Map.Entry) it.next();
            String output = pair.getKey() + "|" + pair.getValue().toString();
            hashMapList.add(output);
            it.remove();
        }

        String hashMapResultString = hashMapList.toString();
        String hashMapResultFormatted = hashMapResultString.replaceAll("[\\[\\]]", "");
        System.out.println(hashMapResultFormatted);

    }

原始列表: customer1^sc1^admin1|server1~customer1^sc1^admin1|server2~customer1^sc1^admin1|server3~customer2^sc1^admin1|server1~customer3^sc1^admin1|server3~customer3^sc1^admin1|server2~

哈希地图字符串:

customer2^sc1^admin1|server1, customer3^sc1^admin1|server3, server2, customer1^sc1^admin1|server1, server2, server3

我现在想使用哈希映射来创建一个将被进一步解析的字符串(不要问lol)。所以我将哈希映射的键和值设置为一个字符串,用独特的分隔符|分隔它们。问题是,因为密钥是List<String>,所以当打印时,如果其值是包含多个项目的列表,则key无法确定每个新customer3^sc1^admin1|server3, server2,的开头。紧接着是customer1^sc1^admin1|server1, server2, server3。我需要一个分隔符来区分它们。

我的理想输出如下:

customer2^sc1^admin1|server1~customer3^sc1^admin1|server3, server2~customer1^sc1^admin1|server1, server2, server3~...

我怎样才能做到这一点?

更新

这是我最终发现对我的特定问题有用的答案:

    StringBuilder s = new StringBuilder();
        for (Map.Entry<String, List<String>> entry : customerHashMap.entrySet()) {
            s.append(entry.getKey() + "|");
            List<String> list = entry.getValue();
            for (String item : list) {
                if (item != list.get(list.size() - 1)) {
                    s.append(item + "^");
                } else {
                    s.append(item);
                }
            }
            s.append("~");
        }
        System.out.println(s.toString());

1 个答案:

答案 0 :(得分:1)

您可以遍历地图的条目集:

StringBuilder s = new StringBuilder();
for(Map.Entry<String,List<String>> entry : map.entrySet()) {
   s.append(entry.getKey() + "\n");
   List<String> list = entry.getValue();
   for(String item : list) {
      s.append("   " + item + "\n");
   }
}
return s.toString();

为了更清楚的示例,我输出的格式与您要求的格式不同,但这说明了如何使用列表值的映射。在根据您的需求进行调整时,请查看java.util.StringJoiner和相关的Collectors.joining();它可能很有用。

Streams在这里很方便:

 String encoded = map.entrySet().stream()
     .map( entry -> entry.getValue().stream()
               .collect(Collectors.joining("^"))
             + "|" + entry.getKey())
     .collect(Collectors.joining("~"));

这里发生的是:

  • 我们从地图中获得了Entry<String,List<String>的流
  • lambda entry -> ...将每个条目转换为val1^v2^v3^...^valN|key形式的字符串,即我们将Stream<Entry<>>映射为Stream<String>
  • 最终collect()使用~作为分隔符将字符串流连接成一个字符串。