Question

我正在努力让游戏对用户想要的船只数量进行输入，并放置那么多船只。我已将坐标放入列表中，这就是我存储它们的方式，并检查它是否是命中。但是这些船只相互叠加，并且使用这种列表方法，我不知道如何首先检查它们是否重叠，其次，更改它们以使它们不重叠。

    from random import randint
    print('Welcome to Battleships for 1 player! Please be careful with entries, as if you get it wrong, you will still lose a go!')
    print('Good luck!')
    print('')
    no_of_goes = int(input("How many goes would you like: "))
    size_of_board = int(input("And how big would you like the board to be: "))
    if size_of_board > 56:
        print("That board will be too big to fit on the screen (max 56)")
        size_of_board = int(input("And choose a more sensible number: "))
    no_of_ships = int(input("And finally, how many ships would you like?: "))
    board = []
    # printing out the board
    for x in range(size_of_board):
        board.append(["O"] * size_of_board)

    def print_board(board):
        for row in board:
            print ("  ".join(row))
    print_board(board)
    # the lists that will become the locations
    ship_rows = []
    ship_cols = []
    # generating random locations
    def random_row(board): 
            return randint(0, len(board) - 1)

    def random_col(board):
            return randint(0, len(board) - 1)
    # adding locations to lists
    ships = list(range(no_of_ships))
    for i in ships:
        row = random_row(board)
        col = random_col(board)
        ship_rows.append(row)
        ship_cols.append(col)
        ##
        ## And this is my attempt (didn't work)
        ##
        for row in ship_cols:
            if row == ship_cols and col == ship_cols:
                ship_rows[-1] = random_row(board)
                ship_cols[-1] = random_col(board)            
    # allowing to see where ships are and logging how many ships have been hit
    print(ship_rows)
    print(ship_cols)
    ship_count = [1]
    ## I couldn't find a way of ending the game once the ships were sunk, so I stuck in a recursive function (sorry)
    def printing_stars():
        print('You have won!! ' +'*' * 56)
        printing_stars()
    for turn in range(no_of_goes):
        # asking for their guesses
        print('Turn ' + str(turn + 1) + ' out of ' + str(no_of_goes))
        guess_col = int(input("Guess Col:")) - 1
        guess_row = int(input("Guess Row:")) - 1
        for item in ship_rows:
            # If they hit, it gives a '!'
            if len(ship_count) == no_of_ships and guess_row == item and guess_col == ship_cols[ship_rows.index(item)]:
                print("You have won!!!! Congratulations")
                board [guess_row][guess_col] = '!'
                print_board(board)
                printing_stars()

            elif guess_row == item and guess_col == ship_cols[ship_rows.index(item)]:
                print ("Congratulations! You sunk one of my battleships")
                board [guess_row][guess_col] = '!'
                print_board(board)
                ship_count.append(1)
                break    
        else:
            # all misses
            if (guess_row < 0 or guess_row > size_of_board - 1) or (guess_col < 0 or guess_col > size_of_board - 1):
                print ("Oops, that's not even in the ocean.")

            elif board[guess_row][guess_col] == "X" or board[guess_row][guess_col] == "!":
                print ("You guessed that one already.")
                turn -= 1
            else:
                print ("You missed my battleship!")
                board[guess_row][guess_col] = "X"
            print_board(board)
            if turn == (no_of_goes - 1):
                print('Game Over')
                break

有什么想法吗？非常感激:)）

Answer 1

您的代码的一些建议：

您可以使用这样的numpy数组为播放器板建模：

尺寸：i line和j colums =＆gt; （i，j）
0如果水
1如果是由palyer拍摄的水
2如果发货unharm
3如果发生船舶案件

一旦他们不再是2，就意味着有一个胜利者。使用此系统，您可以告诉玩家他是否在同一地点拍摄两次，您还可以生成显示。

此外，要随机定位船舶，您可以使用此程序：

设置船舶尺寸：让我们说4个点。
随机选择0或1：0以放置船舶水平位置，选择1以垂直放置船舶

现在我们必须查看它是放置在水平位置还是垂直位置。如果它的位置如下：

在0和j-4之间选择2个随机数，0和i。这将是你的第一个地点坐标，这意味着，这个地点变为2，并且在它之后的3点也是。

5 * 5板的示例，水平船的位置选择（1,0）

我让你处理Verticaly的情况，只需要改变随机数生成索引。

然后，该解决方案不会阻止其他人使用该船。一个简单的解决方案是使用此循环：

while True:
    if all ship placed:
        break

    pick number
    Try to place the ship. (with an if statement, check if one of the spot your gonna change is already a 2.)

只要可以将所有船放在电路板上，该解决方案就应该有效。如果不可能，那么你的循环就不会结束。此外，如果船的数量不受董事会规模的限制，放置它们可能会很长。

然后，您可以使用更复杂的方案继续改进方法。另一个解决方案是在每艘船定位后检查你还有位置。

Python战舰：获取用户输入他们想要的船数

1 个答案: