获取sql

Question

我想获取列上具有最大值的行。我的情况我只想说明有31的X.这是我的代码，也是输出。

create temp view Private(marca) as
    Select a.marca, count(*) as totaleNoleggi, count(distinct a.targa) as totaleAuto, sum(extract(hour from (n.fine-n.inizio))) as totOre
    from auto a join noleggio n on a.targa=n.targa
    group by a.marca;

select marca, totOre
from Private 
group by marca,totore
order by totore desc
limit 1;

    marca   totalenoleggi   totaleauto  totore
1   Audi    1                  1          7
2   BMW     5                  4          7
3   VW      2                  1          1
4   X       2                  1          31

    marca   totore
1   X         31

但这是一个错误的方法，例如没有X，奥迪或宝马有7，但我的选择将打印出第一辆奥迪。所以它是获得最大值的另一种方法

Answer 1

我觉得ALL构造在这里很有用

SELECT marca, totOre
FROM Private 
WHERE totore >= ALL(select totore from private)

Answer 2

您可以使用子查询

select marca, totOre
from Private 
where totore = (select max(totore) from private)

希望它会有所帮助。