Question

我使用TikaParser从'.doc'文件中提取纯文本

public static void main(String[] args) throws Exception {
    ContentHandler handler = new ToHTMLContentHandler();
    AutoDetectParser parser = new AutoDetectParser();
    Metadata metadata = new Metadata();
    ParseContext context = new ParseContext();

    FileInputStream content = new FileInputStream("file.doc");
    parser.parse(content, handler, metadata, context);
    System.out.println(handler.toString());

    String[] metadataNames = metadata.names();
    for (String name : metadataNames) {
        System.out.println(name + " : " + metadata.get(name));
    }

    FileOutputStream outStream = new FileOutputStream("file.doc.txt");
    outStream.write(handler.toString().getBytes());
    outStream.close();
    content.close();
}

这适用于大多数文件，但对于特定文件，它会抛出以下异常

Exception in thread "main" org.apache.tika.exception.TikaException: Unexpected RuntimeException from org.apache.tika.parser.microsoft.OfficeParser@7c417213
at org.apache.tika.parser.CompositeParser.parse(CompositeParser.java:282)
at org.apache.tika.parser.CompositeParser.parse(CompositeParser.java:280)
at org.apache.tika.parser.AutoDetectParser.parse(AutoDetectParser.java:120)
at com.goarya.app.resumestorage.migration.TikaParser.main(TikaParser.java:29)
Caused by: java.lang.IllegalArgumentException: The end (7161) must not be before the start (7162)
at org.apache.poi.hwpf.usermodel.Range.sanityCheckStartEnd(Range.java:208)
at org.apache.poi.hwpf.usermodel.Range.<init>(Range.java:194)
at org.apache.poi.hwpf.usermodel.Paragraph.<init>(Paragraph.java:165)
at org.apache.poi.hwpf.usermodel.Paragraph.newParagraph(Paragraph.java:144)
at org.apache.poi.hwpf.usermodel.Range.getParagraph(Range.java:766)
at org.apache.poi.hwpf.extractor.WordExtractor.getParagraphText(WordExtractor.java:168)
at org.apache.poi.hwpf.extractor.WordExtractor.getMainTextboxText(WordExtractor.java:145)
at org.apache.tika.parser.microsoft.WordExtractor.parse(WordExtractor.java:183)
at org.apache.tika.parser.microsoft.OfficeParser.parse(OfficeParser.java:169)
at org.apache.tika.parser.microsoft.OfficeParser.parse(OfficeParser.java:130)
at org.apache.tika.parser.CompositeParser.parse(CompositeParser.java:280)
... 3 more

在Microsoft Word中打开时，doc文件没有显示错误。

另外，在C＃中使用Microsoft.Office.Interop.Word提供纯文本。

如何使用Apache Tika克服此问题？

修改：为此方案添加sample doc

Answer 1

我正在使用tika cote1.2 jar，我的程序已成功运行以下代码。

import java.io.FileInputStream;
import java.io.FileOutputStream;
import java.io.IOException;

import org.apache.tika.exception.TikaException;
import org.apache.tika.metadata.Metadata;
import org.apache.tika.parser.AutoDetectParser;
import org.apache.tika.parser.ParseContext;
import org.apache.tika.sax.ToHTMLContentHandler;
import org.xml.sax.SAXException;


public class Exmple2 {
     public static void main(final String[] args) throws IOException,TikaException, SAXException {

         ToHTMLContentHandler handler = new ToHTMLContentHandler();
            AutoDetectParser parser = new AutoDetectParser();
            Metadata metadata = new Metadata();
            ParseContext context = new ParseContext();

            FileInputStream content = new FileInputStream("/home/ist/FTRDocuments/taableDis.docx");
            parser.parse(content, handler, metadata, context);
            System.out.println(handler.toString());

            String[] metadataNames = metadata.names();
            for (String name : metadataNames) {
                System.out.println(name + " : " + metadata.get(name));
            }

            FileOutputStream outStream = new FileOutputStream("/home/ist/file.doc.txt");
            outStream.write(handler.toString().getBytes());
            outStream.close();
            content.close();
     }


}

tika1.2唯一改变的是使用ContentHandler的ToHTMLContentHandler。

Java：Apache Tika：从.doc文件中提取文本时出现意外的运行时异常。该文件在MSWord中打开时没有任何错误

1 个答案: