Question

我在员工表中有一个电子邮件列值：

Email
regan.manning@cresa.com
miang.luso@praxis.com
selin.robert@cummins.com

我想将电子邮件拆分为三列，如：

FirstName        LastName              DomainName
--------------------------------------------------
regan            manning               @cresa.com
miang            luso                  @praxis.com
selin            robert                @cummins.com

Answer 1

一种方法使用apply：

select t.*, v.domain, v2.firstname, v2.lastname
from t cross apply
     (values(stuff(email, 1, charindex('@', email), '') as domain,
             left(email, charindex('@', email)
            )
     ) v(domain, name) cross apply
     (values (left(name, charindex('.')),
              stuff(name, 1, charindex('.', name), '')
             )
     ) v2(lastname, firstname;

Answer 2

SELECT 

substring( @email , 0 , CHARINDEX('.' , @email) ) ,

substring( @email , CHARINDEX('.',@email)+1 , CHARINDEX('@' , @email) - CHARINDEX('.' , @email)-1 ),

substring( @email , CHARINDEX('@' , @email) , LEN(@email) - CHARINDEX('@' , @email)+1 )

from employee;

- 将@email替换为您的电子邮件列的名称

更容易理解的版本：

DECLARE @email NVARCHAR(30) = 'selin.robert@cummins.com';
DECLARE @dot INT =CHARINDEX( '.' , @email );
DECLARE @atrate INT =CHARINDEX( '@' , @email );
DECLARE @len INT =LEN( @email );

SELECT 
substring( @email , 0 , @dot ),
substring( @email , @dot+1 , @atrate - @dot-1 ),
substring( @email, @atrate , @len - @atrate+1 );

Answer 3

使用Substring＆amp; Charindex功能检查.，@＆amp;检索数据：

SELECT @email [Email],
       SUBSTRING(@email, 1, CHARINDEX('.', @email)-1) [FirstName],
       SUBSTRING(@email, CHARINDEX('.', @email)+1, CHARINDEX('@', @email)-CHARINDEX('.', @email)-1) [LastName],
       SUBSTRING(@email, CHARINDEX('@', @email), LEN(@email)) [DomainName] from <table_name>;

结果：

Email                   FirstName    LastName   DomainName
miang.luso@praxis.com   miang        luso       @praxis.com

将电子邮件列拆分为Sql Server

3 个答案: