Question

这两个datetime string是平等的。我们如何将这两个字符串datetime与laravel进行比较。

$str_date1='08/09/2017';
$str_date2='8/9/2017';

如何将忽略datetime这两个字符串0与laravel进行比较。

Answer 1

为了达到你所要求的，你需要Carbon课程，你可以尝试这样的事情：

$date1 = Carbon\Carbon::parse($str_date1)->toDateTimeString();
$date2 = Carbon\Carbon::parse($str_date2)->toDateTimeString();
if($date1 == $date2)
{
    // Do your code
}

希望这有帮助

Answer 2

你应该试试这个：

    import { Component, AfterViewInit, AfterContentInit } from '@angular/core';
import { AuthService } from '../../services/auth.service';
import { Router } from "@angular/router";

import * as d3 from "d3-selection";

@Component({
    selector: 'app-dashboard',
    templateUrl: './dashboard.component.html',
    styleUrls: ['./dashboard.component.css']
})

export class DashboardComponent implements AfterViewInit, AfterContentInit {
    user: Object;
    teams: any;

constructor(
    private authService: AuthService,
    private router: Router
) { }

ngAfterContentInit() {
    this.authService.getProfile().subscribe(profile => {
        this.user = profile.user;
    },
        err => {
            console.log(err);
            return false;
        });

    this.authService.getAllTeams().subscribe(teams => {
        // console.log(teams);
        this.teams = Object.keys(teams).map(key => teams[key]);
        // console.log(this.teams);
    },
        err => {
            console.log(err);
            return false;
        });
}

ngAfterViewInit() {
    this.authService.getAllTeams().subscribe(teams => {
        // console.log(this.teams);
        var team = [];
        team = this.teams[0];

        for (var i = 0; i < team.length; i++) {
            var dataset = [];
            dataset = [team[i].spAchieved, team[i].spEstimated];
            // console.log(dataset);

            var w = 100;
            var h = 100;
            var barPadding = 1;

            var svg = d3.select("#chart .list-element:nth-child(" + (i + 1) + ") .graph")
                .append("svg")
                .attr("width", w)
                .attr("height", h);

            svg.selectAll("rect")
                .data(dataset)
                .enter()
                .append("rect")
                .attr("x", (d, i) => i * (w / dataset.length))
                .attr("y", d => h - d)
                .attr("width", w / dataset.length - barPadding)
                .attr("height", d => d)
                .attr("fill", (d) => "rgb(100, 0, " + (d * 5) + ")");

            svg.selectAll("text")
                .data(dataset)
                .enter()
                .append("text")
                .text(d => d)
                .attr("x", (d, i) => i * (w / dataset.length) + 15)
                .attr("y", d => h - d);
        };
    },
        err => {
            console.log(err);
            return false;
        });
}

更新回答：

$str_date1='08/09/2017';
$str_date2='8/9/2017';

$date1 = strtotime($str_date1);
$date2 = strtotime($str_date2);

if($date1 == $date2){
   //Your code
}

Answer 3

将它们转换为DateTime然后进行比较。不需要使用像Carbon或任何花哨类或帮助者那样的东西。

$str_date1 = '08/09/2017';
$str_date2 = '8/9/2017';

$date1 = \DateTime::createFromFormat('d/m/Y', $str_date1);
$date2 = \DateTime::createFromFormat('d/m/Y', $str_date2);

if ($date1 > $date) {
    // Your stuff
}

Answer 4

# Let's first create a list of unsorted data.
# In this case, (A, C, B) are not in lexicographic order.
unsorted_data = [
    'Report1.0REV_A.xlsx',
    'Report1.0REV_C.xlsx',
    'Report1.0REV_B.xlsx',
]


# The function "pick_letter" will be used later on. It is a very simple
# function comprised of only one statement. That is a very good candidate for a
# "lambda expression". But as you say that you are new to Python, I'll give two
# examples below. One using "lambda", the other using the function
# "pick_letter".
def pick_letter(value):
    '''
    This function takes a value and returns the 6th item from the end. The
    value passed can be anythin that can be indexed, like strings or lists.
    '''
    return value[-6]


# Sorting the input data using "pick_letter"
#
# "sorted" takes an optional argument "key" which holds a function. This
# function will be called for each element in the list and must return
# "something". The list will returned by this "something". In your case, you
# want the 6th element from the end, so we use "pick_letter".
sorted_data_1 = sorted(unsorted_data, key=pick_letter)


# As mentioned above, the same can be achieved by a "lambda" expression. This
# saves us the definition of the "pick_letter" function. Using "lambdas" is
# debatable. They have no name, no doc-string and may be harder to understand.
# But this case is *so* simple that it really is a prime candidate for a
# lambda:
sorted_data_2 = sorted(unsorted_data, key=lambda x: x[-6])


print('Unsorted data:', unsorted_data)
print('Sorted data (using pick_letter):', sorted_data_1)
print('Sorted data (using lambda):', sorted_data_2)

# Now that it is sorted, you can pick the last element using [-1]:
print('Last element:', sorted_data_1[-1])


# Apart from sorting, we can create a new list containing only the 6th
# character from the end for each element. The code below is a so called
# "list comprehension". It is a Python feature which allows you to quickly
# create lists (and other similar collections) from other iterables. In
# this case, the list will have the same ordering as the input 
# (unsorted_data)
characters = [filename[-6] for filename in unsorted_data]
print('Characters:', characters)

根据您的需要，PHP附带了区分日期的功能。 http://php.net/manual/en/class.datetime.php

在laravel

4 个答案: