我正在将imageview
保存到图库但是当我保存另一个imageview
时,它将替换之前的版本,我不知道为什么忽略file.createNewFile();
。如何为imageview
保存不同的图像文件?以下代码。
save.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
RelativeLayout content = (RelativeLayout) findViewById(R.id.dashBoard);
content.setDrawingCacheEnabled(true);
Bitmap bitmap = content.getDrawingCache();
File file = new File(Environment.getExternalStorageDirectory().getPath()+ imagename+ ".png");
try {
if (!file.exists()) {
file.createNewFile();
}
FileOutputStream ostream = new FileOutputStream(file);
bitmap.compress(Bitmap.CompressFormat.PNG, 10, ostream);
ostream.close();
content.invalidate();
Toast.makeText(getApplicationContext(), "SAVED", Toast.LENGTH_SHORT).show();
} catch (Exception e) {
e.printStackTrace();
} finally {
content.setDrawingCacheEnabled(false);
}
}
});
答案 0 :(得分:0)
尝试使用UUID.randomUUID()
代替imagename
我认为imagename始终是相同的,这就是为什么它取代旧的
答案 1 :(得分:0)
您可以将当前时间作为文件名::
save.setOnClickListener(new View.OnClickListener() {
@Override
public void onClick(View v) {
RelativeLayout content = (RelativeLayout) findViewById(R.id.dashBoard);
content.setDrawingCacheEnabled(true);
Bitmap bitmap = content.getDrawingCache();
Date d = new Date();
CharSequence imagename = DateFormat.format("MM-dd-yy hh-mm-ss", d.getTime());
File file = new File(Environment.getExternalStorageDirectory().getPath()+ imagename+ ".png");
try {
if (!file.exists()) {
file.createNewFile();
}
FileOutputStream ostream = new FileOutputStream(file);
bitmap.compress(Bitmap.CompressFormat.PNG, 10, ostream);
ostream.close();
content.invalidate();
Toast.makeText(getApplicationContext(), "SAVED", Toast.LENGTH_SHORT).show();
} catch (Exception e) {
e.printStackTrace();
} finally {
content.setDrawingCacheEnabled(false);
}
}
});