Scala(doobie):类型是不变的

时间:2017-08-30 15:27:35

标签: scala doobie

我正在使用Scala和doobie开展项目。我试图实现一个可以由MacWire注入并与不同的任务/未来单子一起使用的交易者特征(例如用于测试)。

import doobie.imports
import doobie.imports._
import fs2.Task
import fs2.util.{Catchable, Suspendable}

trait Transactor[M[_]] {
  implicit def catchable: Catchable[M] = implicitly
  val transactor: M[imports.Transactor[M]]
  def transact[A](q: ConnectionIO[A]): M[A] = catchable.flatMap(transactor)(xa => q.transact(xa))
}

case class H2Transactor[M[_]: Catchable: Suspendable](pure: PureConfig) extends Transactor[M] {
  override val transactor = doobie.h2.imports.H2Transactor[M](
    pure.config.persistence.name,
    pure.config.persistence.user.orNull,
    pure.config.persistence.password.orNull
  )
}

...
trait DatabaseModule { lazy val transactor = wire[H2Transactor[Task]] }
trait TestModule { lazy val transactor = wire[H2Transactor[IOLite]] }

但是我收到了这个错误:

[error] .../src/main/scala/.../persistence/transactor/H2Transactor.scala:13: type mismatch;
[error]  found   : M[doobie.h2.h2transactor.H2Transactor[M]]
[error]  required: M[doobie.imports.Transactor[M]]
[error]     (which expands to)  M[doobie.util.transactor.Transactor[M]]
[error] Note: doobie.h2.h2transactor.H2Transactor[M] <: doobie.imports.Transactor[M], but type M is invariant in type _.
[error] You may wish to define _ as +_ instead. (SLS 4.5)

适用于Task,因为它定义为Task[+A],但是将IOLite定义为IOLite[A]。我能以任何方式使这项工作?或者我 使用不同的Monad类型而不是Task(doobie测试需要更改IOLite)?

1 个答案:

答案 0 :(得分:2)

试试:

override val transactor = doobie.h2.imports.H2Transactor[M](...).widen
如果widencats个实例,

scalaz是一个可用的操作(MFunctor)。如果M[A]M[B]

的子类,则可以将A视为B