有一个列名为" phone"并且具有不同格式的不同数字。
示例:
id | number
1 | 03439879098
2 | 01109890032
3 | +91 932 3233237
现在,如果我想搜索" 3233237"然后查询将是:
select * from table where number like '%3233237%';
结果将是:
id | number
3 | +91 932 3233237
但在我的情况下,我想反向
String search = "+92 343 9879098"
select * from table where number like search
结果应为:
id | number
1 | 03439879098
因为列数字和搜索字符串有一个共同的字符串, 9879098 。
查询的设计应使其查找搜索字符串和列值都具有公共子字符串的记录
请给我一些想法。
答案 0 :(得分:1)
This was a tricky one. You can do it in pure SQL executing:
# Create a forwarded port mapping which allows access to a specific port
# within the machine from a port on the host machine. In the example below,
# accessing "localhost:8080" will access port 80 on the guest machine.
# config.vm.network "forwarded_port", guest: 80, host: 8080
# nginx
config.vm.network "forwarded_port", guest: 80, host: 6600
# # development site
config.vm.network "forwarded_port", guest: 3000, host: 6660
# db browser port
config.vm.network "forwarded_port", guest: 7474, host: 6666
# test port
config.vm.network "forwarded_port", guest: 8800, host: 6606
Here we're concatenating the number column with the wildcards %.
*Also You could resolve it programatically:
dropdownMenu.dataSource = self;
dropdownMenu.delegate = self;
Cheers.
答案 1 :(得分:-1)
您是否尝试过NOT LIKE
,因此它会像
select * from table where name not like search