<?php
define('HOST','localhost');
define('USER','id2553362_hcoe');
define('PASS','admin');
define('DB','id2553362_hamrosadhan');
$con = mysqli_connect(HOST,USER,PASS,DB) or die('Unable to Connect');
$jsondata = file_get_contents("php://input");
$data = json_decode($jsondata,true);
$bookeduser = $data['BookedUser'];
$bookfrom = $data['BookedFrom'];
$bookto = $data['BookTo'];
$category = $data['Category'];
$ulat = $data['ULat'];
$ulong = $data['ULong'];
$sql = "SELECT PostId,VehicleName,VechicleID,Category,Location,
Description,RateAmount, AvailableFrom,AvailableTo, ( 6371 * acos( cos(
radians($ulat) ) * cos( radians(LocationLat ) ) *
cos( radians( LocationLong ) - radians($ulong) ) +
sin( radians($ulat) )*
sin( radians(LocationLat ) ) ) ) AS distance FROM VehicleDetails WHERE
Category='$category' AND AvailableFrom <= '$bookfrom' AND AvailableTo >=
'$bookto' HAVING distance < 500 ";
$query = mysqli_query($con, $sql) or die('query fails');
if($query){
while($vinfo = mysqli_fetch_array($query))
{
var_dump($vinfo);die;
}
}
?>
我希望我的代码使用查询过滤器返回表中的所有数据,但我的查询只返回1个数据。 输出:
array(20) {
[0]=>
string(1) "3"
["PostId"]=>
string(1) "3"
[1]=>
string(5) "cbras"
["VehicleName"]=>
string(5) "cbras"
[2]=>
string(11) "ba56psa2437"
["VechicleID"]=>
string(11) "ba56psa2437"
[3]=>
string(8) "2 wheels"
["Category"]=>
string(8) "2 wheels"
[4]=>
string(7) "gongabu"
["Location"]=>
string(7) "gongabu"
[5]=>
string(12) "got conditon"
["Description"]=>
string(12) "got conditon"
[6]=>
string(4) "5000"
["RateAmount"]=>
string(4) "5000"
[7]=>
string(10) "2017-09-15"
["AvailableFrom"]=>
string(10) "2017-09-15"
[8]=>
string(10) "2017-10-15"
["AvailableTo"]=>
string(10) "2017-10-15"
[9]=>
string(18) "0.8621561884069938"
["distance"]=>
string(18) "0.8621561884069938"
}
答案 0 :(得分:1)
取下模具;来自while循环,并把它放在}
下面if($query){
while($vinfo = mysqli_fetch_array($query)) {
var_dump($vinfo);
}
die();
}