Question

您好我正在使用数据网格在WPF中显示可观察的集合。现在我如何从DataGrid中获取所选的行文本，以便我可以调用一个函数。这是我的XAML：

<DataGrid x:Name="dataGrid" HorizontalAlignment="Left" Margin="0,77,0,0" VerticalAlignment="Top" Height="720" Width="664" ItemsSource="{Binding Items}" AutoGenerateColumns="False" Grid.ColumnSpan="2" SelectedCellsChanged="dataGrid_SelectedCellsChanged">
        <DataGrid.Columns>
            <DataGridTextColumn Header="ProjectName" MinWidth="100" Binding="{Binding Path=ProjectName,Mode=TwoWay}" IsReadOnly="True"></DataGridTextColumn>
            <DataGridTextColumn Header="Name" MinWidth="100" Binding="{Binding Path=Name,Mode=TwoWay}" IsReadOnly="True"></DataGridTextColumn>
            <DataGridTextColumn Header="Path" MinWidth="460" Binding="{Binding Path=Path,Mode=TwoWay}" IsReadOnly="True"></DataGridTextColumn>
        </DataGrid.Columns>
    </DataGrid>

如何从所选单元格或行中获取文本？

Answer 1

由于WinForms DataGridView比static更灵活，获取值似乎很难。因此，我制作了以下SelectedRow 扩展名方法/功能，以获得SelectedCell，SelectedCellValue＆amp; GetVisualChild。对于public static T GetVisualChild<T>(Visual parent) where T : Visual { T child = default(T); int numVisuals = VisualTreeHelper.GetChildrenCount(parent); for (int i = 0; i < numVisuals; i++) { Visual v = (Visual)VisualTreeHelper.GetChild(parent, i); child = v as T; if (child == null) { child = GetVisualChild<T>(v); } if (child != null) { break; } } return child; }以及下面给出的一些功能，我在SO中看到了一些帖子。

SelectedRow

获取public static DataGridRow GetSelectedRow(this DataGrid grid) { return (DataGridRow)grid.ItemContainerGenerator.ContainerFromItem(grid.SelectedItem); }：

DataGridRow

当您知道RowIndex：

时获取

public static DataGridRow GetRow(this DataGrid grid, int index)
{
     DataGridRow row = (DataGridRow)grid.ItemContainerGenerator.ContainerFromIndex(index);
     if (row == null)
     {
        grid.UpdateLayout();
        grid.ScrollIntoView(grid.Items[index]);
        row = (DataGridRow)grid.ItemContainerGenerator.ContainerFromIndex(index);
     }
     return row;
}

DataGridCell

获得DataGridRow和columnIndex后的public static DataGridCell GetCell(this DataGrid grid, DataGridRow row, int columnIndex) { if (row != null) { DataGridCellsPresenter presenter = GetVisualChild<DataGridCellsPresenter>(row); if (presenter == null) { grid.ScrollIntoView(row, grid.Columns[columnIndex]); presenter = GetVisualChild<DataGridCellsPresenter>(row); } DataGridCell cell = (DataGridCell)presenter.ItemContainerGenerator.ContainerFromIndex(columnIndex); return cell; } return null; }：

DataGridCell

获得DataGridRow和columnName后的public static DataGridCell GetCell(this DataGrid grid, DataGridRow row, string columnName) { int index = grid.Columns.Single(c => c.Header.ToString().ToUpper() == columnName.ToUpper()).DisplayIndex; return GetCell(grid, row, index); }：

DataGridCell

获得rowIndex和columnIndex后的public static DataGridCell GetCell(this DataGrid grid, int row, int column) { DataGridRow rowContainer = grid.GetRow(row); return grid.GetCell(rowContainer, column); }：

DataGridCellValue

获得DataGridRow和ColumnName后的public static string GetCellValue(this DataGrid grid, DataGridRow row, string columnName) { int index = grid.Columns.Single(c => c.Header.ToString().ToUpper() == columnName.ToUpper()).DisplayIndex; DataGridCell dgc = GetCell(grid, row, index); string str = Convert.ToString(((TextBlock)dgc.Content).Text); return str; }：

DataGridCellValue

获得rowIndex和ColumnName后的public static string GetCellValue(this DataGrid grid, int rowIndex, string columnName) { DataGridRow row = grid.GetRow(rowIndex); int columnIndex = grid.Columns.Single(c => c.Header.ToString().ToUpper() == columnName.ToUpper()).DisplayIndex; DataGridCell dgc = GetCell(grid, row, columnIndex); string str = Convert.ToString((TextBlock)dgc.Content); return str; }：

$result = DB::table('users')
        ->join('role_user', 'users.id', '=', 'role_user.user_id')
        ->where('role_user.role_id', $roleId)        
        ->join('roles', 'role_user.role_id', '=', 'roles.id')
        ->select('users.*','role_user.role_id','roles.display_name','roles.description')           
        ->get();

Answer 2

您应该使用默认的CollectionView作为数据源。假设它被称为项目，您可以使用：

var cv = (CollectionView)CollectionViewSource.GetDefaultView(Items);
var currentItem = (YourItemType)cv.CurrentItem;

Answer 3

如果您绑定的Items集合是IEnumerable<T>，则可以将SelectedItem的{{1}}属性转换为DataGrid：

或者您可以将YourItemType obj = dataGrid.SelectedItem as YourItemType; string name = obj.Name;属性绑定到类型为SelectedItem的属性，就像绑定T属性一样：

ItemsSource

从Datagrid单元格或行获取文本

3 个答案: