Question

我有以下用于处理文件帖子的方法：

        public string Message(Stream data)
        {


            int length = 0;
            using (FileStream writer = new FileStream("test.zip", FileMode.Create))
            {
                int readCount;

                var buffer = new byte[8 * 16];
                while ((readCount = data.Read(buffer, 0, buffer.Length)) != 0)
                {
                    writer.Write(buffer, 0, readCount);
                    length += readCount;
                }
            }

            return "test";


        }

使用这个我可以发布邮递员的文件。当我检查另一侧发布的zip文件时，一切看起来都不错，可以打开zip文件而不会出错。这是我用来从C＃客户端发布文件的代码：

        using (WebClient clientFile = new WebClient())
        {
            clientFile.UploadFileAsync(new Uri("http://192.168.122.146:8000/Message"), "test.zip");
        }

文件已上传但当我想打开时会显示错误消息：“压缩（压缩）文件夹无效或已损坏”。有没有办法上传文件而不使用multipart / form-data？该代码适用于邮递员但如果我从C＃客户端上传文件则无效。以下是来自Fiddler的请求：

POST http://192.168.122.146:8000/Message HTTP/1.1
Host: 192.168.122.146:8000
Connection: keep-alive
Content-Length: 8505677
Cache-Control: no-cache
Origin: chrome-extension://fhbjgbiflinjbdggehcddcbncdddomop
User-Agent: Mozilla/5.0 (Windows NT 6.3; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/60.0.3112.113 Safari/537.36
Postman-Token: 4d0e5489-7818-226f-6f71-b9bee2947905
Accept: */*
Accept-Encoding: gzip, deflate
Accept-Language: en-US,en;q=0.8

来自C＃客户端的请求：

POST http://192.168.122.146:8000/PutMessage HTTP/1.1
Content-Type: multipart/form-data; boundary=---------------------8d4ef8a23bf0f80
Host: 192.168.122.146:8000
Content-Length: 8505848
Expect: 100-continue
Connection: Keep-Alive

-----------------------8d4ef8a23bf0f80
Content-Disposition: form-data; name="file"; filename="test.zip"

发布没有multipart / form-data的二进制数据

0 个答案: