Question

所以我有这段代码：

$q = mysqli_query($connection ,"insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'longitude','30');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'latitude','30');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'tagline','doctor');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'verify_user','on');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'contact_form','off');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'first_name','$doctor_name');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'address','$address');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'phone_number','$mobile');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'nickname','$doctor_name');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'user_type','professional');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'profile_status','active');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'directory_type','127');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'user_profile_specialist','$specialicity');
    insert into wp_abzj_usermeta (user_id,meta_key,meta_value) VALUES ($last_id,'$specialicity','$specialicity')                  
");

所以到现在为止，我应该有一个菜单，它将在用户输入中读取，直到用户键入0.但是，我不希望用户输入0（整数）退出，而是希望代码在用户输入时停止＆＃39; X＆＃39; （一个人物）。有没有办法做到这一点？我是Java的新手。

Answer 1

您可以使用nextInt()而不是next()。因此，您的选择需要定义为String。在此之后，即使输入1或2之类的数字，这些数字也将作为字符串处理。之后，您可以使用＆＃34; 1＆＃34;和＃34; x＆＃34;。

Answer 2

您应该使用scanner.nextLine().charAt(0)而不是scanner.next().charAt(0)，因为接下来不会使用换行符并且可以跳过您的新输入

Answer 3

似乎你想接受混合输入，包括文本（＆＃34; x＆＃34;）和整数。

hasNextLine()类有一些实用程序方法可以在使用之前检测扫描程序输入，例如hasNextInt()或if (scanner.hasNextInt()) { // It's an integer int choice = scanner.nextInt(); switch (choice) { ... } } else { // A scanner input is always parseable as a string String choice = scanner.nextLine(); if (Objects.equals(choice, "x")) { // Stop, exit, return, terminate and abort } else { // What happens if the user entered an invalid string? // You decide! } }。使用这些方法，您可以轻松检测是否输入了有效的菜单选项：

Scanner scanner = new Scanner(int);
while (scanner.hasNext()) {
    ...
}

进一步评论

每次迭代，您都会创建一个新的Scanner实例。这是不必要的开销。您最好只创建一个扫描仪，然后重复接受输入：

<?php 

//username and password of account
$username = trim($_POST["email"]);
$password = trim($_POST["password"]);
echo "username=$username pass:$password";
$loginUrl = 'https://www.pogrande.com/login.php?action=process';
//The username or email address of the account.
define('USERNAME', $username);

//The password of the account.
define('PASSWORD', $password);

//Set a user agent. This basically tells the server that we are using Chrome ;)
define('USER_AGENT', 'Mozilla/5.0 (Windows NT 5.1) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.2309.372 Safari/537.36');

//Where our cookie information will be stored (needed for authentication).
define('COOKIE_FILE', 'cookie.txt');

//URL of the login form.
define('LOGIN_FORM_URL', 'https://www.pogrande.com/login.php');

//Login action URL. Sometimes, this is the same URL as the login form.
define('LOGIN_ACTION_URL', 'https://www.pogrande.com/login.php?action=process');


//An associative array that represents the required form fields.
//You will need to change the keys / index names to match the name of the form
//fields.
$postValues = array(
    'email_address' => USERNAME,
    'password' => PASSWORD
);

//Initiate cURL.
$curl = curl_init();

//Set the URL that we want to send our POST request to. In this
//case, it's the action URL of the login form.
curl_setopt($curl, CURLOPT_URL, LOGIN_ACTION_URL);

//Tell cURL that we want to carry out a POST request.
curl_setopt($curl, CURLOPT_POST, true);

//Set our post fields / date (from the array above).
curl_setopt($curl, CURLOPT_POSTFIELDS, http_build_query($postValues));

//We don't want any HTTPS errors.
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);

//Where our cookie details are saved. This is typically required
//for authentication, as the session ID is usually saved in the cookie file.
curl_setopt($curl, CURLOPT_COOKIEJAR, COOKIE_FILE);

//Sets the user agent. Some websites will attempt to block bot user agents.
//Hence the reason I gave it a Chrome user agent.
curl_setopt($curl, CURLOPT_USERAGENT, USER_AGENT);

//Tells cURL to return the output once the request has been executed.
curl_setopt($curl, CURLOPT_RETURNTRANSFER, true);

//Allows us to set the referer header. In this particular case, we are 
//fooling the server into thinking that we were referred by the login form.
curl_setopt($curl, CURLOPT_REFERER, LOGIN_FORM_URL);

//Do we want to follow any redirects?
curl_setopt($curl, CURLOPT_FOLLOWLOCATION, true);

//Execute the login request.
curl_exec($curl);
$status = curl_getinfo($curl, CURLINFO_HTTP_CODE);
echo "status=$status"; 
//Check for errors!
if(curl_errno($curl)){
    throw new Exception(curl_error($curl));
}

$url = $_POST['url'];   
$content = $outp;//json_encode("your data to be sent");

//We should be logged in by now. Let's attempt to access a password protected page
curl_setopt($curl, CURLOPT_URL, $url);

//Use the same cookie file.
curl_setopt($curl, CURLOPT_COOKIEJAR, COOKIE_FILE);

//Use the same user agent, just in case it is used by the server for session validation.
curl_setopt($curl, CURLOPT_USERAGENT, USER_AGENT);

//We don't want any HTTPS / SSL errors.
curl_setopt($curl, CURLOPT_SSL_VERIFYHOST, false);
curl_setopt($curl, CURLOPT_SSL_VERIFYPEER, false);
curl_setopt($curl, CURLOPT_POST, true);
curl_setopt($curl, CURLOPT_POSTFIELDS, $content);

//Execute the GET request and print out the result.
curl_exec($curl);//the login is now done and you can continue to get the
//protected content.

/*
$url = $_POST['url'];    
$content = $outp;//json_encode("your data to be sent");
curl_setopt($ch, CURLOPT_URL, $url);

curl_setopt($ch, CURLOPT_HEADER, false);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_HTTPHEADER,
        array("Content-type: application/json"));
curl_setopt($ch, CURLOPT_POST, true);
curl_setopt($ch, CURLOPT_POSTFIELDS, $content);
*/
$json_response = curl_exec($curl);

$status = curl_getinfo($curl, CURLINFO_HTTP_CODE);

if ( $status != 201 ) {
    die("Error: call to URL $url failed with status $status, response $json_response, curl_error " . curl_error($curl) . ", curl_errno " . curl_errno($curl));
}


curl_close($curl);

$response = json_decode($json_response, true);
//alert($response);*/
}
}

?>

您应该正确格式化代码。错误的缩进很容易让其他读者感到困惑，包括你自己。

带有Integer和Char的Java菜单

3 个答案:

进一步评论