我已经被困了几个小时,现在试图从一个阵列(玩家)中随机选择一个项目(团队1)。
我已经通过使用splice做了其他工作,但不幸的是,splice创建了一个带有删除项目的数组,所以我最终获得了一个带有数组的数组。
这是我到目前为止所得到的:
var players = ["P1", "P2", "P3", "P4"];
var team1 = [];
var team2 = [];
var select = Math.floor(Math.random() * players.length);
var tmp;
if (team1.length < 2) {
tmp.push(players.splice(select, 1));
team1.push(tmp.pop);
}
console.log(team1);
console.log(tmp);
console.log(players);
如果我这样做是对的,我很抱歉,对这个网站来说还是一个新手,感谢您的帮助。
答案 0 :(得分:1)
你在场景中尝试这样做
var players = ["P1", "P2", "P3", "P4"];
var team1 = [];
var team2 = [];
var temp = players.slice();
for(i=0; i<temp.length; i++){
var select = Math.floor(Math.random() * temp.length);
console.log(select);
if (team1.length <= temp.length/2) {
team1.push(temp[select]);
}
temp.splice(select, 1);
}
team2 = temp.slice();
console.log('team 1 ---',team1);
console.log('team 2 ---',team2);
console.log('players ---', players);
答案 1 :(得分:1)
您只需在拼接并推送到团队时选择阵列中的第一个元素,
var players = ["P1", "P2", "P3", "P4", "P5", "P6", "P7", "P8"];
var team1 = [];
var team2 = [];
var tmp = [];
while (team1.length < 4) {
tmp.push(players.splice(Math.floor(Math.random() * players.length - 1), 1)[0]);
team1.push(tmp.pop());
}
while (team2.length < 4) {
tmp.push(players.splice(Math.floor(Math.random() * players.length - 1), 1)[0]);
team2.push(tmp.pop());
}
console.log(team1);
console.log(team2);
console.log(tmp);
console.log(players);